Homework Help is Here – Start Your Trial Now!
Math
Calculus
1. Cos ax dr = sin ax + C 2. sin ax dx -- cos ax + C %3D a a 4. csc ar de 1 = -- cot ax + C 3. ax dx = - tan ax + C a a 1 csc ax + C a 5. sec ax tan ax dx =- sec ax + C 6. csc ax cot ax= a dr = + C 1 + + C, b > 0, b + 1 In b 7. ar + C 8. h dr = a dx dr 9. at + x + C = sin- + C, a > 0 10. tan a %3! a* - x dx 11. -- - - seC + C, a > 0 xV a a a dx, b > 0, b + 1

1. Cos ax dr = sin ax + C 2. sin ax dx -- cos ax + C %3D a a 4. csc ar de 1 = -- cot ax + C 3. ax dx = - tan ax + C a a 1 csc ax + C a 5. sec ax tan ax dx =- sec ax + C 6. csc ax cot ax= a dr = + C 1 + + C, b > 0, b + 1 In b 7. ar + C 8. h dr = a dx dr 9. at + x + C = sin- + C, a > 0 10. tan a %3! a* - x dx 11. -- - - seC + C, a > 0 xV a a a dx, b > 0, b + 1

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.5: Product-to-sum And Sum-to-product Formulas
Problem 2E
See similar textbooks
icon
Related questions
Question

Find formulas for the following general indefinite integrals to verify results (7), (8), and (10) in Table shown

1. Cos ax dr = sin ax + C 2. sin ax dx -- cos ax + C %3D a a 4. csc ar de 1 = -- cot ax + C 3. ax dx = - tan ax + C a a 1 csc ax + C a 5. sec ax tan ax dx =- sec ax + C 6. csc ax cot ax= a dr = + C 1 + + C, b > 0, b + 1 In b 7. ar + C 8. h dr = a dx dr 9. at + x + C = sin- + C, a > 0 10. tan a %3! a* - x dx 11. -- - - seC + C, a > 0 xV a a a
Transcribed Image Text:1. Cos ax dr = sin ax + C 2. sin ax dx -- cos ax + C %3D a a 4. csc ar de 1 = -- cot ax + C 3. ax dx = - tan ax + C a a 1 csc ax + C a 5. sec ax tan ax dx =- sec ax + C 6. csc ax cot ax= a dr = + C 1 + + C, b > 0, b + 1 In b 7. ar + C 8. h dr = a dx dr 9. at + x + C = sin- + C, a > 0 10. tan a %3! a* - x dx 11. -- - - seC + C, a > 0 xV a a a
dx, b > 0, b + 1
Transcribed Image Text:dx, b > 0, b + 1
Expert Solution
steps

Step by step

Solved in 2 steps with 2 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer