1. Convert the following moisture content as indicated. Show your solutions. a. 18% wb to MCdb b. 26% wb to MCdb 15% db to MCwb с. d. 20% db to MCwb e. 24% db to MCwb 2. Determine the weight loss of a ton of paddy at 24% if dried to 14%. Correspondingly, determine the price at different level. Considering price difference of P2.00/kg between wet and dry. Make your conclusion from the above figures. 3. From a one hectare farm, 150 bags (50kg/bag) of palay were harvested with moisture content of 26%MCwb. If it will be dry to 14%MC, determine how much water will be removed from drying? 4. One hundred (100) bags of freshly harvested palay was dried to 14%MC and became 90 bags. Determine the fresh moisture content before drying. 5. Two tons of paddy with 22% moisture content on wet basis is to be dried to 13% moisture content on dry basis. Calculate the weight of bone dry products and water evaporated. 6. Determine the quantity of parboiled paddy with 40% moisture content on wet basis required to produce 1 ton of product with 12% moisture content on wet basis. Work out the problem on wet basis and check the answer using dry basis. 7. Draw a graph showing moisture content of grain on wet basis versus moisture content on dry basis. Take the moisture content of grain on wet basis from 10% to 60% at equal intervals of 5%.
1. Convert the following moisture content as indicated. Show your solutions. a. 18% wb to MCdb b. 26% wb to MCdb 15% db to MCwb с. d. 20% db to MCwb e. 24% db to MCwb 2. Determine the weight loss of a ton of paddy at 24% if dried to 14%. Correspondingly, determine the price at different level. Considering price difference of P2.00/kg between wet and dry. Make your conclusion from the above figures. 3. From a one hectare farm, 150 bags (50kg/bag) of palay were harvested with moisture content of 26%MCwb. If it will be dry to 14%MC, determine how much water will be removed from drying? 4. One hundred (100) bags of freshly harvested palay was dried to 14%MC and became 90 bags. Determine the fresh moisture content before drying. 5. Two tons of paddy with 22% moisture content on wet basis is to be dried to 13% moisture content on dry basis. Calculate the weight of bone dry products and water evaporated. 6. Determine the quantity of parboiled paddy with 40% moisture content on wet basis required to produce 1 ton of product with 12% moisture content on wet basis. Work out the problem on wet basis and check the answer using dry basis. 7. Draw a graph showing moisture content of grain on wet basis versus moisture content on dry basis. Take the moisture content of grain on wet basis from 10% to 60% at equal intervals of 5%.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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100%
The second picture is for formula only. Thank you.

Transcribed Image Text:1. Convert the following moisture content as indicated. Show your solutions.
a. 18% wb to MCdb
b. 26% wb to MCdb
15% db to MCwb
d. 20% db to MCwb
e. 24% db to MCwb
2. Determine the weight loss of a ton of paddy at 24% if dried to 14%. Correspondingly,
determine the price at different level. Considering price difference of P2.00/kg between
wet and dry. Make your conclusion from the above figures.
3. From a one hectare farm, 150 bags (50kg/bag) of palay were harvested with moisture
content of 26%MCwb. If it will be dry to 14%MC, determine how much water will be
removed from drying?
4. One hundred (100) bags of freshly harvested palay was dried to 14%MC and became
90 bags. Determine the fresh moisture content before drying.
5. Two tons of paddy with 22% moisture content on wet basis is to be dried to 13%
moisture content on dry basis. Calculate the weight of bone dry products and water
evaporated.
6. Determine the quantity of parboiled paddy with 40% moisture content on wet basis
required to produce 1 ton of product with 12% moisture content on wet basis. Work out
the problem on wet basis and check the answer using dry basis.
7. Draw a graph showing moisture content of grain on wet basis versus moisture content
on dry basis. Take the moisture content of grain on wet basis from 10% to 60% at equal
intervals of 5%.
c.

Transcribed Image Text:Moisture content wet basis - commercial
Ww
Ww
х 100% —
Wt
%MCwb
x 100%
Ww + Wd
2. Moisture content dry basis – research
Ww
Ww
x 100%
Wd
%MCdb
х 100%
Wt – Ww
Where:
Ww= weight of water
Wt = total weight
Wd = weight of dry matter – will not change at any level of moisture
Determination of water removed:
Wr = Wd (AMCdb)
Conversion
WB to DB
Ww/Wt
Ww
Wt
Ww
Ww
MCwb
%MCdb
Wd
Wt – Ww
Wt
1— Мсwb
Wt
DB to WB
Ww
Ww
Ww/Wd
MCdb
%MCwb
Wt
Ww + Wd
Ww
Wd
MCdb + 1
Wd + wd
Example: one hectare farm
100 bags (50kg/bag) at 24%MCwb
moisture content
after/during harvesting objective: to dry to 14%MC – MC safe for storage determine how much
water will be removed from drying and the final weight.
100 bags @ 50kg/bag = 5000 kg At 24%
Ww24%
Ww24% = MCwb (Wt)
0.24
= Ww24%+Wd
0.24(5000 kg) = 1,200 kg
Wd = Wt – Ww= 5,000 – 1,200 = 3,800 kg
At 14%
Ww14%
0.14
= Ww14%+Wd
Ww14%
0.14 = Ww14%+3,800 kg
Ww14 = 0.14(Ww14 + 3,800kg)
0.86WW14 = 0.14(3,800 kg) Ww14
= 618.6 kg
Wr = 1200 – 618.6 = 581.4kg/50 bags
Wf= 5,000 – 581.4 = 4,418 kg
11 bags
Convert wet basis(commercial) to dry basis (research)
MCdb24 = 31.6%
MCdb14 = 16.3%
Wr = Wd (AMCdb) = 3,800 (0.316 – 0.163) = 581.4kg
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