1.)     Consider the endothermic reaction 4HCl (aq) + MnO2 (s) <=> Cl2 (g) + 2 H2O (l) + MnCl2 (aq), The reaction can be moved to the left (reactants) by___________         a. Increasing the temperature         b. Adding H2O         c. Increasing the pressure         d. Removing Cl2

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1.)     Consider the endothermic reaction 4HCl (aq) + MnO2 (s) <=> Cl2 (g) + 2 H2O (l) + MnCl2 (aq),

The reaction can be moved to the left (reactants) by___________

        a. Increasing the temperature

        b. Adding H2O

        c. Increasing the pressure

        d. Removing Cl2

2.)  The free energy change, ∆Go for a reaction is –255 kJ. The reaction is therefore________

        a.Exothermic

        b.Irreversible

        c. Spontaneous

        d.Endothermic

 3.)    When the equilibrium constant, Kc, for a reaction is large, the value of ∆Go is___________

        a. large and negative

        b. small and negative

        c.  zero

        d. large and positive

4.)  If the pOH is 3, the [H3O+] is _________ M

        a.  10-3

        b. 10-8

        c. 3

        d. 10-11

5.)    What is the conjugate acid of CO 3 -2?

        a. CO 2 -2

        b. HCO 2 -2

        c. H 2CO 3

        d. HCO 3 -

6.)  What change will be caused by addition of a small amount of HCl to a solution containing fluoride ions and hydrogen fluoride?

       a. The concentration of fluoride ions will increase as will the concentration of hydronium ions

       b. The concentration of hydrogen fluoride will decrease and the concentration of fluoride ions will increase

       c. The concentration of fluoride ion will decrease and the concentration of hydrogen fluoride will increase

       d. The concentration of hydronium ions will increase significantly

7.)   How many moles of NaF should be added to 500.0 ml 0.40 M HF to create a buffer where the pH equals the pKa of HF?

       a. 0.40

       b. 0.050

       c. 0.10

       d. 0.20

8.)  Will Cu (s) reduce Sn4+ ions to Sn2+ ions, based on these reduction potentials:

     Cu2+ (aq)/Cu (s)  Eo = +0.34 V

     Sn4+ (aq)/Sn2+ (aq)  Eo = +0.15 V

       a. Yes, because Ecell is negative

       b. Yes, because Ecell is positive

       c. No, because Ecell is negative

       d. No, because Ecell is positive

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