1. Consider the circuit below. The battery has an emf of = 30.00 V and an internal resistance of r = 1.00 Q. R₂ = 18.00 A 15 = ε = 30.00 V QQQQQQ = 1.00 ΩΣ R₁10.00 (a) Find the equivalent resistance of the circuit and the current out of the battery. Reg Q |= A (b) Find the potential drop across each resistor. V₁= V₁= V₂= V₂= V4= V₁ = (c) Find the current through each resistor. 1₁= 4₁ = 1₂= 13= = V V V V V < < (d) Find the power dissipated by each resistor. P,= W R₁9.00 3 W W R3 - 10.00 Ω W W W R₁ = 8.000 www P₁ = (e) Find the total power supplied by the battery. Psup W
1. Consider the circuit below. The battery has an emf of = 30.00 V and an internal resistance of r = 1.00 Q. R₂ = 18.00 A 15 = ε = 30.00 V QQQQQQ = 1.00 ΩΣ R₁10.00 (a) Find the equivalent resistance of the circuit and the current out of the battery. Reg Q |= A (b) Find the potential drop across each resistor. V₁= V₁= V₂= V₂= V4= V₁ = (c) Find the current through each resistor. 1₁= 4₁ = 1₂= 13= = V V V V V < < (d) Find the power dissipated by each resistor. P,= W R₁9.00 3 W W R3 - 10.00 Ω W W W R₁ = 8.000 www P₁ = (e) Find the total power supplied by the battery. Psup W
College Physics
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Chapter1: Units, Trigonometry. And Vectors
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![1. Consider the circuit below. The battery has an emf of ε = 30.00 V and an internal resistance of r = 1.00
Q Q
P₂²
=
00
ε = 30.00 V
· 1.00 ΩΣ
=
V
R₁ = 10.00
(a) Find the equivalent resistance of the circuit and the current out of the battery.
Rea
Q
|=
A
(b) Find the potential drop across each resistor.
V₁=
V₁ =
V₂ =
V₂ =
V₂ =
V₁=
(c) Find the current through each resistor.
| =
4₁₂ =
1₂ =
V
V
V
V
D D D D D
15 =
(d) Find the power dissipated by each resistor.
P₁=
P₁
+|1||
W
W
W
W
R₁
W
W
=
R310.00 23
R5 = 8.00
www
P₁ =
(e) Find the total power supplied by the battery.
W
9.00 23
R₂ = 18.00 0](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc2daf8f3-113d-48f5-9b15-0b37d7046821%2F33f8eddd-a0c4-46dd-8ae4-f3d9ed1de9f9%2Fnc84xq_processed.png&w=3840&q=75)
Transcribed Image Text:1. Consider the circuit below. The battery has an emf of ε = 30.00 V and an internal resistance of r = 1.00
Q Q
P₂²
=
00
ε = 30.00 V
· 1.00 ΩΣ
=
V
R₁ = 10.00
(a) Find the equivalent resistance of the circuit and the current out of the battery.
Rea
Q
|=
A
(b) Find the potential drop across each resistor.
V₁=
V₁ =
V₂ =
V₂ =
V₂ =
V₁=
(c) Find the current through each resistor.
| =
4₁₂ =
1₂ =
V
V
V
V
D D D D D
15 =
(d) Find the power dissipated by each resistor.
P₁=
P₁
+|1||
W
W
W
W
R₁
W
W
=
R310.00 23
R5 = 8.00
www
P₁ =
(e) Find the total power supplied by the battery.
W
9.00 23
R₂ = 18.00 0
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