1. Consider a 4 digit number abcd and show that abcd−(a+b+c+d) is always divisible by 9. (Ex 1234 − 10 = 1224 = 9 · 136).
1. Consider a 4 digit number abcd and show that abcd−(a+b+c+d) is always divisible by 9. (Ex 1234 − 10 = 1224 = 9 · 136).
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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1. Consider a 4 digit number abcd and show that abcd−(a+b+c+d) is always
divisible by 9. (Ex 1234 − 10 = 1224 = 9 · 136).
2. (A) How many different three-letter initials can a person have?
(B) What if the initials are not repeated?
(C) What if only consecutive initials are not repeated?
( please just answer part c on this one.. A and B are just so you know the entire question)
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