1. Consider a 1 bit error correcting Hamming code. Let the codeword be 7 bits and the message 1100. Find the codeword - show all work - use a diagram like in the book.
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- A Gray code is a sequence of binary numbers with the property that no more than 1 bit changes in going from one element of the sequence to another. For example, here is a 3-bit binary Gray code: 000, 001, 011, 010, 110, 111, 101, and 100. Using three D flip-flops and a PLA, construct a 3-bit Gray code counter that has two inputs: reset, which sets the counter to 000, and inc, which makes the counter go to the next value in the sequence. Note that the code is cyclic, so that the value after 100 in the sequence is 000.Implement the design of a 2-bit binary subtractor meaning a 2-bit subtracted by another 2-bit. The 2-bit minuend are labeled AB (A = MSB, B = LSB) and the 2-bit subtrahend are labeled CD (C = MSB, D = LSB) and the 4-bit difference is labeled as WXYZ (W = MSB, Z = LSB). Any negative value answers should display in 1's complement.Write a java program to give your own example of Bitwise complement operators.Give source code and output also.
- Describe a device from everyday life that can be in either of two states, such as a flag on a flagpole that is either up or down. Assign the symbol 1 to one of the states and 0 to the other, and show how the ASCII representation for the letter b would appear when stored with such bits.Implement code convertor Y=(X+4) mod 8 using decoder and encoder. Y and X are 3-bit numbers.ASCII Codes can be helpful to find binary code of different decimal numbers and alphabets etc. You have to consider 65 and its equivalent code of 16 bits will be considered for bit sequence and a divisor for CRC. Follow this process; first 8 bits will be used for data while next 4 bits will be used for divisor (if there are 4 zeroes in your case then replace with 1001), neglect last 4 bits. Also check your answer.
- Find the representation x of the following signed numbers listed below in the base specified on the right. a.- (01100110)2=( x )10 b.- (10110111)2=( x )10 C.- (207)10=( x )2 d.- (-135)10=(× )2 e.- (2D7)16=( x )2 f.- (10110011)2=(x )16 g.- (-5.5)10=( x )2 e.- (11000001010000000000000000001010)2=(x )10 Note: In part e the binary representation on the left corresponds to a real number representation.Computer sciencewrite out work and show work
- In the Hamming coding system (7.3), its representation is expressed as 3 control (test) bits and 7 total bits (data+control bits).In the literature, control bits are represented as (cl, c2, c3, or (pl, p2, p3, .) The bit string sent by encoding with Hamming coding (15,4) is on the receiving side, It is retrieved as 001100101100 (pl.p2.dll). According to this bit sequence;Which option is given according to the control bits (p1.p2.p3.p4) sequence of the received bit sequence?A 0110B 1100C 1001D 0011E 0010Consider a 16-bit binary floating point number representation system: + | SE E E E E E m m т m m m m m m The first bit of the exponent is dedicated to its sign. Assume that the mantissa must start with a '1'. Use this system to answer the following question What is the smallest (magnitude) number that can be represented with this system?Please please don't copy Computer Science for BCH (16,12). when input is (0, 4, 14, 14, 4, 4, 15, 2, 4, 2, 15, 13), what are the check digits?