1. COMPUTE for the CLx, UCLx, LCLx, CLr, UCLr, LCLr. Show all computations.

A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
icon
Related questions
Question
100%

Q4.1 PLEASE PROVIDE HANDWRITTEN SOLUTIONS

A manufacturing firm that produces steel cabinets would like to implement variable
control chart in their fabrication metal corporation. Based on the monthly
summary of the QC report, the number one cause of rejection is mis-alignment due
to wrong diameter. Thus, a variable control chart shall be implemented to monitor
the stability of the fabrication process to consistently achieve the standard
diameter. Their plan is to visit the power press machine, randomly pick 6 samples
and measure their individual diameters. The result of their initial data gathering is
shown below:
subgroup Xave
Xh
XI
18.70
1
19.87
22.10
18.08 21.20
17.26
20.63
20.73
20.14
21.57
24.46 19.86
20.62
23.42 19.47
20.07
21.07 18.33
20.80 21.34 19.69
18.06
20.95
16.87
18.65
21.14
16.89
20.92
23.42 18.68
2
3
4
5
6
7
8
9
10
subgroup
12
13
14
15
16
17
18
19
20
Xh
XI
Xave
21.65 24.37
18.96
21.85 22.28 20.15
21.47
23.67
19.99
21.53 22.64
18.07
20.14
23.06 18.76
20.51
22.85
18.87
20.74
23.43
18.25
19.04 20.44
18.01
19.72
22.88
17.97
18.30 21.66 15.84
Note: Xaverage = the average measurements for the 6 samples per subgroup, Xh=
the highest measurement of the 6 samples, XI = the lowest measurement of the 6
samples taken
1. COMPUTE for the CLx, UCLx, LCLx, CLr, UCLr, LCLr. Show all computations.
Transcribed Image Text:A manufacturing firm that produces steel cabinets would like to implement variable control chart in their fabrication metal corporation. Based on the monthly summary of the QC report, the number one cause of rejection is mis-alignment due to wrong diameter. Thus, a variable control chart shall be implemented to monitor the stability of the fabrication process to consistently achieve the standard diameter. Their plan is to visit the power press machine, randomly pick 6 samples and measure their individual diameters. The result of their initial data gathering is shown below: subgroup Xave Xh XI 18.70 1 19.87 22.10 18.08 21.20 17.26 20.63 20.73 20.14 21.57 24.46 19.86 20.62 23.42 19.47 20.07 21.07 18.33 20.80 21.34 19.69 18.06 20.95 16.87 18.65 21.14 16.89 20.92 23.42 18.68 2 3 4 5 6 7 8 9 10 subgroup 12 13 14 15 16 17 18 19 20 Xh XI Xave 21.65 24.37 18.96 21.85 22.28 20.15 21.47 23.67 19.99 21.53 22.64 18.07 20.14 23.06 18.76 20.51 22.85 18.87 20.74 23.43 18.25 19.04 20.44 18.01 19.72 22.88 17.97 18.30 21.66 15.84 Note: Xaverage = the average measurements for the 6 samples per subgroup, Xh= the highest measurement of the 6 samples, XI = the lowest measurement of the 6 samples taken 1. COMPUTE for the CLx, UCLx, LCLx, CLr, UCLr, LCLr. Show all computations.
Expert Solution
steps

Step by step

Solved in 4 steps with 1 images

Blurred answer