This is part of a review I'm studying, NOT a graded assignment, please do not reject. Thank you for your help!I only need the last two out of the five sub-parts, I already got a solution for the first three sub-parts. Thank you again for your help! 1. Circuit analysis using phasor/impedance, complex power calculation: An RLC circuit is shownbelow. The reactance of the capacitor is 40 Ohm. The reactance of the inductor is 80 Ohm, and the resistoris 8 Ohm. The sending end voltage is v₁ (t) = 343 cos(wt + 7) kV, where w = 2 - 60 rad/s. The receiving endvoltage is v₂ (t) = 3 cos (wt) kV. Ask:• What is the total impedance of the RLC circuit at 60 Hz? What are the sending end and receiving endvoltage phasors in kV?• Please find the current through the line in phasor and in time-domain and in unit kA.• What is the complex power S₁? What is the complex power S₂? Please use a unit of MVA.• What is the power loss due to the resistor? What is the reactive power consumption by the inductor?How much reactive power is generated by the capacitor?• For the same sending end voltage and receiving end voltage, if the series capacitor is not installed, whatis the real power delivered to the receiving end? Please compare this number with the one from the seriescompensated case, compare the current magnitude and the net reactance of the RL circuit and the RLCcircuit, and state the advantage of series compensation.fVs~S₁RL Cmm tS₂

Answered: 1. Circuit analysis using…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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This is part of a review I'm studying, NOT a graded assignment, please do not reject. Thank you for your help!

I only need the last two out of the five sub-parts, I already got a solution for the first three sub-parts. Thank you again for your help!

1. Circuit analysis using phasor/impedance, complex power calculation: An RLC circuit is shown
below. The reactance of the capacitor is 40 Ohm. The reactance of the inductor is 80 Ohm, and the resistor
is 8 Ohm. The sending end voltage is v₁ (t) = 343 cos(wt + 7) kV, where w = 2 - 60 rad/s. The receiving end
voltage is v₂ (t) = 3 cos (wt) kV. Ask:
• What is the total impedance of the RLC circuit at 60 Hz? What are the sending end and receiving end
voltage phasors in kV?
• Please find the current through the line in phasor and in time-domain and in unit kA.
• What is the complex power S₁? What is the complex power S₂? Please use a unit of MVA.
• What is the power loss due to the resistor? What is the reactive power consumption by the inductor?
How much reactive power is generated by the capacitor?
• For the same sending end voltage and receiving end voltage, if the series capacitor is not installed, what
is the real power delivered to the receiving end? Please compare this number with the one from the series
compensated case, compare the current magnitude and the net reactance of the RL circuit and the RLC
circuit, and state the advantage of series compensation.
f
Vs
~
S₁
RL C
mm t
S₂

Expert Solution

Step 1: Determine the given variables:-

Solution of all the five parts is as below:

The RLC circuit is shown below,

$Capacitive space reactance comma space straight X subscript straight C equals 40 space straight capital omega. Inductive space reactance comma space straight X subscript straight L equals 80 space straight capital omega. Resistor comma space straight R equals 8 space space straight capital omega. Sending space end space voltage comma space straight v subscript 1 open parentheses straight t close parentheses equals fraction numerator 345 over denominator square root of 3 end fraction cos open parentheses straight omega straight t plus straight pi over 6 close parentheses space kV. Receiving space end space voltage comma space straight v subscript 2 open parentheses straight t close parentheses equals fraction numerator 345 over denominator square root of 3 end fraction cos open parentheses straight omega straight t close parentheses space kV. Where comma straight omega equals 2 straight pi times 60 space rad divided by sec.$ a

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