Ethyl acetate (CH3COOC2H5) was synthesizedby Sir Yowjin in a non-reacting solvent (notwater) according to the following reaction:CH3COOH(aq) +C2H5OH(ag) = CH3COOC2H5(aq) + H2O(aq)For the following mixtures (1-3) that he made,will the concentration of acetic acid(CH3COOH) increase, decrease, or remain thesame as equilibrium is established?(Keg forthe reaction = 2.2) 1. [CH3COOC2H5] = 0.22 M; [CH3COOH] =0.010 M; [С2Н5ОН] — 0.010 M; [Н0] 30.10 М2. [CH3COOC2H5] = 0.22 M; [CH3COOH] =0.0020 M; [С2H5ОН] — 0.10 M%; [Н0]3%3|0.0020 М3. [CH3COOC,H5] = 4.4 M; [CH3COOH] =0.88 M; [C2H5ОН] — 10.0 М; [Н20] %3D4.4M

Given equilibrium reaction is CH3COOH (aq) +C2H5OH (aq)⇔CH3COOC2H5 (aq) + H2O (aq) Equilibrium…

1. [CH3COOC2H5] = 0.22 M; [CH3COOH] = 0.010 M;B [С2H5ОН] — 0.010 М;B [H20] %3 0.10 М 2. [CHзCOOC2Hs] %3D 0.22 M; [СH3СООН] — 0.0020 M; [C2Н5ОН] — 0.10 М; [H20] 3D II 0.0020 М 3. [CH3COOC2H5] = 4.4 M; [CH3COOH] = %3D 0.88 M;B [С2H50Н] — 10.0 М;B [Н20]%3D 4.4 M

1. [CH3COOC2H5] = 0.22 M; [CH3COOH] = 0.010 M;B [С2H5ОН] — 0.010 М;B [H20] %3 0.10 М 2. [CHзCOOC2Hs] %3D 0.22 M; [СH3СООН] — 0.0020 M; [C2Н5ОН] — 0.10 М; [H20] 3D II 0.0020 М 3. [CH3COOC2H5] = 4.4 M; [CH3COOH] = %3D 0.88 M;B [С2H50Н] — 10.0 М;B [Н20]%3D 4.4 M

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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