1. Calculate the pressure of 3.50 Liters of a gas at 25.0 C if it has a volume of 4.50 Liters at STP. Hint: the temperature and pressure of STP is in your notes. (Combined) 2. A gas occupies 35.1 Liters at a temperature of 105.0 °C. What will its volume be if it is cooled to 25.0 C? (Charles Law)

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### Gas Laws Problem Set

#### Problem 1: Combined Gas Law Calculation

**Question:**  
Calculate the pressure of 3.50 Liters of a gas at 25.0°C if it has a volume of 4.50 Liters at STP. Hint: the temperature and pressure of STP is in your notes. (Combined)

**Details:**  
To solve this problem, you will use the Combined Gas Law:

\[ \frac{P_1 \cdot V_1}{T_1} = \frac{P_2 \cdot V_2}{T_2} \]

Where:
- \(P_1\) and \(P_2\) are the initial and final pressures,
- \(V_1\) and \(V_2\) are the initial and final volumes,
- \(T_1\) and \(T_2\) are the initial and final temperatures (in Kelvin).

Convert temperatures to Kelvin (K = °C + 273).

#### Problem 2: Charles' Law Calculation

**Question:**  
A gas occupies 35.1 Liters at a temperature of 105.0°C. What will its volume be if it is cooled to 25.0°C? (Charles Law)

**Details:**  
To solve this problem, you will use Charles' Law:

\[ \frac{V_1}{T_1} = \frac{V_2}{T_2} \]

Where:
- \(V_1\) and \(V_2\) are the initial and final volumes,
- \(T_1\) and \(T_2\) are the initial and final temperatures (in Kelvin).

Convert temperatures to Kelvin (K = °C + 273).

For both problems, ensure to solve for the unknown variable by appropriately rearranging the given equation. Additionally, make sure to maintain consistent units throughout the calculation.
Transcribed Image Text:### Gas Laws Problem Set #### Problem 1: Combined Gas Law Calculation **Question:** Calculate the pressure of 3.50 Liters of a gas at 25.0°C if it has a volume of 4.50 Liters at STP. Hint: the temperature and pressure of STP is in your notes. (Combined) **Details:** To solve this problem, you will use the Combined Gas Law: \[ \frac{P_1 \cdot V_1}{T_1} = \frac{P_2 \cdot V_2}{T_2} \] Where: - \(P_1\) and \(P_2\) are the initial and final pressures, - \(V_1\) and \(V_2\) are the initial and final volumes, - \(T_1\) and \(T_2\) are the initial and final temperatures (in Kelvin). Convert temperatures to Kelvin (K = °C + 273). #### Problem 2: Charles' Law Calculation **Question:** A gas occupies 35.1 Liters at a temperature of 105.0°C. What will its volume be if it is cooled to 25.0°C? (Charles Law) **Details:** To solve this problem, you will use Charles' Law: \[ \frac{V_1}{T_1} = \frac{V_2}{T_2} \] Where: - \(V_1\) and \(V_2\) are the initial and final volumes, - \(T_1\) and \(T_2\) are the initial and final temperatures (in Kelvin). Convert temperatures to Kelvin (K = °C + 273). For both problems, ensure to solve for the unknown variable by appropriately rearranging the given equation. Additionally, make sure to maintain consistent units throughout the calculation.
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