1. Calculate the inverse Laplace transform: -4s +3 (a) L-1. 2s² + 2s +5 4s² 10s +16 (b) L-1 (s²-4) (s+1),

Q: 4x-y<-1

A: Given  4x-y&lt;1 Can be rewritten as y&gt;4x-1 So we take the area above the line y = 4x -1 And all…

Q: Let Rt) be the inverse Laplace transform of 7s2 + 15s – 6 F(s) = (s? + 6s + 10)(s – 2) What is 3/2)?

A:

Q: Find the inverse Laplace transform of: 1 1+2s (a) (b) s+7 - 2 s+4 (c) (d) s' +6s +10 s' + 2s +5

A:

Q: Find the inverse Laplace transform of -1344+192s-5s5 -7s5+56

A: We have to find the inverse Laplace transform of the function.

Q: (c) Find the inverse Z-transform of Y(2) (32 – 1)(2+4)*

A:

Q: Find the inverse Laplace transform of each function: -4s a) F(s) = -5/2.

A: We find out the Laplace inverse transform .

Q: Find the inverse Laplace transform of 42s + 34 (s – 3)(s² + 2s + 5)

A:

Q: Calculation: Rewrite the given function. Y [s] = 2s+3 s²+s+1 2s+1+2 e

A:

Q: 3. Find the inverse Laplace transform. a) 8s2 − 4s + 12/s(s2 + 4)

A:

Q: Find the inverse Transform F (6) = 6s s?+25 3. s²+25 S + 2

A: Note the result :

Q: 2) Find the inverse Laplace transform of -2= 2(s+1)e 4e (s+1)² +16 -45 S+5

A: