1. Calculate the energy released by the reaction given in sample problem 12 and compare it to the energy released by the alpha decay of californium–252.
1. Calculate the energy released by the reaction given in sample problem 12 and compare it to the energy released by the alpha decay of californium–252.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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1. Calculate the energy released by the reaction given in sample problem 12 and compare it to the energy released by the alpha decay of californium–252.

Transcribed Image Text:25Cf → 1Xe + 19Ru +4 ¿n
108Ru + 4 on
253Cf → 28Cm + He
Cm + ¿He
96
Isotope
Atomic Mass (u)
252Cf
98
252.081626
140
Xe
139.92165
108RU
44
107.91017
248Cm
96
248.072349
He
4.001506

Transcribed Image Text:Sample Problem 12
The spontaneous fission of californium-252 releases xenon-140 and
i ruthenium-108. How many neutrons are released in this process?
Writing the following reaction, we have
252Cf → 140Xe + 10°Ru + ? ¿n
Adding the atomic numbers, we could see that the totals are balanced.
For the mass numbers
252 = 140 + 108 + (x)(1)
in which x is the number of neutrons. Solving for x
252 = 248 + x =x= 252 – 248 = 4
Therefore, there are four neutrons that are products of the reaction.
The balanced reaction is
252Cf
108
140y
54Xe +
Ru + 4 ¿n
98
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