1. Calculate the collision frequency, z, and the collision density, ZAA, in carbon monoxide, d = 260 pm, at 30°C and 120 kPa. What is the percentage increase when the temperature is raised by 10K at constant volume?
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- A tank contains 16 moles of neon gas at an absolute pressure of 1 x 105 Pa. What is the change in the internal energy of the gas when the temperature is raised from 27 ºC to 32 ºC. Given: Boltzmann constant: k = 1.38 x 10–23 J/K, Ideal Gas Constant: R = 8.31 J/(mol K) 1000 J B. 750 J C. 500 J D. 250 J E. 100 JFor this question there could be one or MULTIPLE answers, Choose the best Match/Matches. For a monatomic ideal gas in thermal equilibrium near room temperature, a. U = 3/2 NkT. b. U = 5/2 NkT. c. degrees of freedom include translational and rotational motions. d. degrees of freedom include translational, rotational, and vibrational motions. e. U = 5/2 pV. f. U = 3/2 pV. Explain work please.a) Calculate the mean free path in meters of a nitrogen molecule (with a mass m=4.68×10¬26 kg) located in Earth's atmosphere at sea level. Assume a temperature of T=300 K and a number density of particles of 1019 cm-3. b) Assuming that the collision cross-section of the molecule is o = 2x10-10 frequency v in Hertz and the time between collisions t in seconds. m, compute the collision
- 1. An ideal gas is at a temperature of 350 K. To double the rms speed of its molecules, what does the temperature need to be changed to? K T=* ? 63. During isothermal compression, the internal energy of an ideal gas : a. Decreases b. Can go either way depending on the precise pressures and volumes c. Stays the same d. Increases 64. What is the total internal energy of a sample of 9 moles of air (considered as an ideal gas) at a temperature of 3°C? Assume that the rotational degrees of freedom are fully activated, and that the vibrational modes are "frozen out". (k=1.38 x 10-23 J/K, N-6.022x10²3) 3°C = 273+3 = 276 U= n NAF ( 1₂ KT) (9)(6.022 X 10²²) x 1.38×10²³ x 276) = 1032 a. 1.19 x 105 J b. 9.29 x 104 J c. 7.23 x 104 J d. 5.16 x 104 J 65. What is the average translational kinetic energy per oxygen molecule in this sample? a. 1.2 x 10-20 J b. 9.14 x 10-21 J c. 5.71 x 10-21 J d. 1.54 x 10-20 J 66. Is this kinetic energy the same or different from the nitrogen molecules in the sample? a. Different b. The same 67. What is the rms speed of the oxygen molecules in this sample? (the atomic mass number of oxygen is 15.994, 1 u =…15. The adiabatic index of a gas is given by which of the following? a. Cp/Cv b. Cv/Cp C. Cp-Cv d. Cpt Cv O B D OA OC Question 10 C
- 5. A gas with volume V, pressure P, and temperature T is inside a container with a moveable piston. No gas is leaking from the container as the temperature of gas is quadrupled while the volume is doubled. What will be the new pressure? A. 2P B. P C. 1/2 P D. 8PWhat is the relative humidity on a 30.0 °C day when the air contains 12 g/m³ of water vapor? The vapor pressure of water at 30.0 °C is Py = 4.24 × 10 Pa and the molecular mass of water is M = 18.0 g/mol. % relative humidity:1. For nitrogen at 283 K find, a) The most probable speed ✔m/s b) The average speed m/s c) The rms speed m/s The molar mass of nitrogen is 14.0 g/mol and R= 8.31 kg/(mol K) Hint: You need to convert quantities into SI units.