1. Calculate the average titer (mg CaCO3/mL EDTA) for the three trials. P.S. Please do refer to the image attached to complete the calculation of this number. 2. A 30.0 mL portion of the water sample was titrated with the standardized EDTA solution. Total hardness was calculated for each of the three trials and summarized in the table below: Calculate the amount of titrant used in each trial to reach endpoint. Trial 1: Total Hardness - 1203.19 ppm Trial 2: Total Hardness - 1210.81 ppm Trial 3: Total Hardness - 1208.17 ppm 3. Report total hardness of the sample as mean ±sd.
1. Calculate the average titer (mg CaCO3/mL EDTA) for the three trials. P.S. Please do refer to the image attached to complete the calculation of this number. 2. A 30.0 mL portion of the water sample was titrated with the standardized EDTA solution. Total hardness was calculated for each of the three trials and summarized in the table below: Calculate the amount of titrant used in each trial to reach endpoint. Trial 1: Total Hardness - 1203.19 ppm Trial 2: Total Hardness - 1210.81 ppm Trial 3: Total Hardness - 1208.17 ppm 3. Report total hardness of the sample as mean ±sd.
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Be able to answer the question below and show your complete solution:
1. Calculate the average titer (mg CaCO3/mL EDTA) for the three trials.
- P.S. Please do refer to the image attached to complete the calculation of this number.
2. A 30.0 mL portion of the water sample was titrated with the standardized EDTA solution. Total hardness was calculated for each of the three trials and summarized in the table below: Calculate the amount of titrant used in each trial to reach endpoint.
Trial 1: Total Hardness - 1203.19 ppm
Trial 2: Total Hardness - 1210.81 ppm
Trial 3: Total Hardness - 1208.17 ppm
3. Report total hardness of the sample as mean ±sd.
![We will calculate the [Ca2*] in the primary standard first.
Molar mass of CaCO3 = 100.09 g/mol
Weight of CaCO3 used = 0.125 g
Vol. of solution = 250.0 mL
Molarity of CaCOg solution = (0.125/ 100.09) / (250.0 / 1000) = 0.004996M
Molarity of [Ca?*] = 0.004996M
EDTA forms a 1:1 complex with [Ca²*]).
M;V1 = M2V2
where 1 is for the EDTA solution
2 is for the CaCOg solution
Trial 1
0.009981 x V, = 0.004996 x 25.0
V, = 12.5 mL
Trial 2
0.009862 x V, = 0.004996 x 25.0
V, = 12.7 mL
Trial 3
0.01029 x V, = 0.004996 x 25.0
V, = 12.1 mL](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc7d69999-dec1-47c6-ace3-9bad836a2785%2F4872263f-9267-49f1-8e96-4013b5a1252b%2F91wptju_processed.png&w=3840&q=75)
Transcribed Image Text:We will calculate the [Ca2*] in the primary standard first.
Molar mass of CaCO3 = 100.09 g/mol
Weight of CaCO3 used = 0.125 g
Vol. of solution = 250.0 mL
Molarity of CaCOg solution = (0.125/ 100.09) / (250.0 / 1000) = 0.004996M
Molarity of [Ca?*] = 0.004996M
EDTA forms a 1:1 complex with [Ca²*]).
M;V1 = M2V2
where 1 is for the EDTA solution
2 is for the CaCOg solution
Trial 1
0.009981 x V, = 0.004996 x 25.0
V, = 12.5 mL
Trial 2
0.009862 x V, = 0.004996 x 25.0
V, = 12.7 mL
Trial 3
0.01029 x V, = 0.004996 x 25.0
V, = 12.1 mL
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