Give typed solution 1. Calculate pH of pure water open to the atmosphereCO2(dissolved) + H₂O+ H₂O → H₂CO3CO2(air)CO2(dissolved)H₂CO3H+ + HCO3¯H+ + CO3™HCO3KH = [H₂CO3]/Pc02K3 = [H][ HCO3 ]/[ H₂CO3]K4 = [H ][ CO3 ]/[HCO3]Given:-1.47KH=10 M/atm-4Pco2 = 3x10 atm-6.35K3 = 10Assumption: when Pco2 is not too low, [H*] = [HCO3]

Solutions- We have to calculate the pH of the pure water open to the atmosphere.

1. Calculate pH of pure water open to the atmosphere: CO2(dissolved) + H₂O CO2(air) со 2(dissolved) + H₂O H₂CO3 H+ + HCO3* HCO3* →H+ +CO3™ -1.47 H₂CO3 KH = [H₂CO3]/PCO2 K3 = [H][ HCO3 ]/[ H₂CO3] K4 = [H][ CO3 ]/[HCO3] Given: KH=10 M/atm Pco2 = 3x10 atm -6.35 (1) (2) (3) (4) K3 = 10 Assumption: when Pco2 is not too low, [H] = [HCO3]

1. Calculate pH of pure water open to the atmosphere: CO2(dissolved) + H₂O CO2(air) со 2(dissolved) + H₂O H₂CO3 H+ + HCO3* HCO3* →H+ +CO3™ -1.47 H₂CO3 KH = [H₂CO3]/PCO2 K3 = [H][ HCO3 ]/[ H₂CO3] K4 = [H][ CO3 ]/[HCO3] Given: KH=10 M/atm Pco2 = 3x10 atm -6.35 (1) (2) (3) (4) K3 = 10 Assumption: when Pco2 is not too low, [H] = [HCO3]

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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