1. Arun incorrectly writes log, x+log, y -log, z as a single logarithm. log , x+log, y-log, z = log, (x+y-z) Where did Arjun make errors? Explain his errors and the properties oflogarithms that leads to the correct answer. State the correct answer. Answer. (Score for Question 2: of 7 points) 2. Helen and Stephen both simplify the exponential expression Helen: e2-1 ela e Stephen: e n2-1 (2)-1 =e- Un fortunately, they both made an error. Identify where each person made his or her error and explain in words what he or she did wrong. Then, correctly simplify the expression.

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**1.** Arjun incorrectly writes \( \log_7 x + \log_7 y - \log_7 z \) as a single logarithm.

\[
\log_7 x + \log_7 y - \log_7 z = \log_7 (x + y - z)
\]

Where did Arjun make errors? Explain his errors and the properties of logarithms that lead to the correct answer. State the correct answer.

**Answer:**

Arjun made an error by incorrectly applying the properties of logarithms. The correct property for combining logarithms is: 

- \(\log_b m + \log_b n = \log_b (mn)\)
- \(\log_b m - \log_b n = \log_b \left(\frac{m}{n}\right)\)

Thus, the correct expression should be:

\[
\log_7 x + \log_7 y - \log_7 z = \log_7 \left(\frac{xy}{z}\right)
\]

**2.** (Score for Question 2: ___ of 7 points)

Helen and Stephen both simplify the exponential expression \( e^{\frac{4}{3}n^2-1} \).

**Helen:**

\[
e^{\frac{4}{3}n^2-1} = \frac{e^{\frac{4}{3}n^2}}{e} = \frac{2^4}{e} = \frac{\sqrt[3]{8}}{e}
\]

**Stephen:**

\[
e^{\frac{4}{3}n^2-1} = e^{3} \cdot e^{-1} = e^3 = e^{\frac{5}{2}} = e^{e\sqrt{2}}
\]

Unfortunately, they both made an error. Identify where each person made his or her error and explain in words what he or she did wrong. Then, correctly simplify the expression.

**Answer:**

- **Helen's Error:** Helen incorrectly interpreted the expression's exponent and simplified it inconsistently with exponential rules. The attempt to express the result as \(\frac{\sqrt[3]{8}}{e}\) implies a misunderstanding of exponent rules.

- **Stephen's Error:** Stephen's work showed the incorrect simplification by treating \(e^{\frac{4}{3}n^2-
Transcribed Image Text:**1.** Arjun incorrectly writes \( \log_7 x + \log_7 y - \log_7 z \) as a single logarithm. \[ \log_7 x + \log_7 y - \log_7 z = \log_7 (x + y - z) \] Where did Arjun make errors? Explain his errors and the properties of logarithms that lead to the correct answer. State the correct answer. **Answer:** Arjun made an error by incorrectly applying the properties of logarithms. The correct property for combining logarithms is: - \(\log_b m + \log_b n = \log_b (mn)\) - \(\log_b m - \log_b n = \log_b \left(\frac{m}{n}\right)\) Thus, the correct expression should be: \[ \log_7 x + \log_7 y - \log_7 z = \log_7 \left(\frac{xy}{z}\right) \] **2.** (Score for Question 2: ___ of 7 points) Helen and Stephen both simplify the exponential expression \( e^{\frac{4}{3}n^2-1} \). **Helen:** \[ e^{\frac{4}{3}n^2-1} = \frac{e^{\frac{4}{3}n^2}}{e} = \frac{2^4}{e} = \frac{\sqrt[3]{8}}{e} \] **Stephen:** \[ e^{\frac{4}{3}n^2-1} = e^{3} \cdot e^{-1} = e^3 = e^{\frac{5}{2}} = e^{e\sqrt{2}} \] Unfortunately, they both made an error. Identify where each person made his or her error and explain in words what he or she did wrong. Then, correctly simplify the expression. **Answer:** - **Helen's Error:** Helen incorrectly interpreted the expression's exponent and simplified it inconsistently with exponential rules. The attempt to express the result as \(\frac{\sqrt[3]{8}}{e}\) implies a misunderstanding of exponent rules. - **Stephen's Error:** Stephen's work showed the incorrect simplification by treating \(e^{\frac{4}{3}n^2-
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