1. Are there any points in time when the object will be not in motion? (i.e. when its velocity is zero) 2. What are the position, speed and acceleration of this object at t=5s.
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- 5. An object is launched 15 m/s horizontally. A. Fill in the variables for the object. B. Solve for time in the y-direction. C. Since the x-direction is constant speed, solve for Ax.1. It takes you 10 min to walk with an average velocity of 2 m/s to The North from The Grocery Shop to your house. What is your displacement?9. A particle currently has positive displacement and negative velocity and always has constant positive acceleration. Which one of the following statements must be true about the particle? A. Its speed is currently increasing. B. Its speed is currently decreasing. C. Its velocity will always be negative. D. Its displacement will eventually become negative.
- i need help with Only the last 3 parts ( C D and E)12. A ball is thrown straight up into the air. At each of the following instants, is the magnitude of the ball's acceleration greater than g, equal to g, less than g, or 0? Explain. a. Just after leaving your hand. b. At the very top (maximum height). 6. Just before hitting the ground.Q1.An electron, in a picture tube of a TV set, travelling in a straight line, accelerates uniformly from speed 4.3x10^4 to 9.0x10^6 m/s along a lenght of 2.3 cm. (15) a. How much time does the electron spend in this 2 cm region? b. What is the magnitude of the electron's acceleration?
- 2. A car is traveling down a long, straight road at 15 m/s (about 25 mph) when the driver sees an obstacle and brakes to a stop at a rate of 10 m/s² (magnitude). A typical driver has a reaction time of 0.5 s, that is it takes them this long after seeing the obstacle before they apply the brakes. 1. What is the minimum stopping distance for the above driver? 2. What would be the minimum stopping distance if the driver is initially traveling at 30 m/s instead of 15 m/s?15. A ball is hit upward with an initial velocity of 128 feet per second. After t seconds, its height h(t) is given by the function h(t) = -16t?+128t+4. What is the maximum height in feet of the ball? a. 268 feet b. 256 feet C. 264 feet d. 260 feet4. A robotic vehicle is exploring the surface of Mars. The robot, which is represented as a point, has x - and y-coordinates that vary with time: x = (3 − 2t); y = (-t² + 4t³) where x and y are in meters and t is in seconds. a. Find the average velocity of the robot between t = 0s and t = 2s. b. Find the average acceleration of the robot between t = 0s and t = 2s. c. At what time the acceleration of the robot will be zero. a. Vavg= -21 + 14ĵ m/s b. davg = 22ĵ C. m s² 2 t = = = 0.083 s 24
- 4. Marcus throws a rock straight up into the air. It leaves his hand 1.2 meters above the ground, and it hits the ground 3.5 seconds later. Find a. the initial speed of the rock when it leaves his hand b. the maximum height the rock reaches before falling back down, relative to the ground c. the speed of the rock right before it hits the groundIf the velocity is constant towards the right direction, the graph of displacement x vs time t is a A. line with a positive slope. B. line with negative slope. C. parabola in the first quadrant. O D. parabola in the 4th quadrant. An object is moving towards the right direction. Velocity is constant. The graph of velocity vs time t is a line O A. along the t axis B. parallel to the t axis C. parallel to the v axis. O D. with nonzero slope. Velocity of a moving object is towards the right. Velocity is constant. The graph of acceleration a vs time t is a A. line parallel to the acceleration a axis. B. line along the acceleration a axis. C. line along the t-axis. OD.line with positive slope.1. The acceleration of a car is given by a(t) = A – Bt + Ct² , where A = 1.0 m/s², B = 0.5 m/s³, C = 2.0 m/s“. The car is at rest at the origin at time t= 0. Find its position and velocity as a function of time. b. Sketch its position, velocity, and acceleration. a.