1. An RLC circuit consists of a resistor, inductor, and a capacitor in series alongwith a battery as their components. Expressed from total energy, we see thetotal charge as determined by the differential equationdd qdq+R+= 0dt2dtShow that from the general solution for a harmonic oscillator under a dampedoscillation with the expression that is analogous,d²xdx+ bdt2dt= 0,m+ kx =gives us the solution of charge as,-R/2Lq(t) = Qmazecos wat,where the angular frequency of the circuit is211/2R1= PMLC2LHint: Start with working through finding a general solution for the harmonicoscillator for mechanical energy. Apply it to Electromagnetic energy to find thesolution above. We can find that this type of solution is similar.

An LCR circuit is one that has all three components: Inductor (L), Capacitor (C), and Resistor (R).…

1. An RLC circuit consists of a resistor, inductor, and a capacitor in series along with a battery as their components. Expressed from total energy, we see the total charge as determined by the differential equation dd²q L +R- + dt2 dt Show that from the general solution for a harmonic oscillator under a damped oscillation with the expression that is analogous, d²x dx +b + kx = 0, dt m- dt² gives us the solution of charge as q(t) = Qmaze¬R/2L cos wat, %3D where the angular frequency of the circuit is 271/2 R 1 wd LC 2L Hint: Start with working through finding a general solution for the harmonic oscillator for mechanical energy. Apply it to Electromagnetic energy to find the solution above. We can find that this type of solution is similar.

1. An RLC circuit consists of a resistor, inductor, and a capacitor in series along with a battery as their components. Expressed from total energy, we see the total charge as determined by the differential equation dd²q L +R- + dt2 dt Show that from the general solution for a harmonic oscillator under a damped oscillation with the expression that is analogous, d²x dx +b + kx = 0, dt m- dt² gives us the solution of charge as q(t) = Qmaze¬R/2L cos wat, %3D where the angular frequency of the circuit is 271/2 R 1 wd LC 2L Hint: Start with working through finding a general solution for the harmonic oscillator for mechanical energy. Apply it to Electromagnetic energy to find the solution above. We can find that this type of solution is similar.