1. An object is moving along a straight line and its velocity at time t is given by: v(t) = t² − 4t - 5 (a) Find the displacement from t = 3 to t = 6. (b) Find the distance travelled from t = 3 to t = 6.

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**Velocity and Displacement Analysis**

1. An object is moving along a straight line, and its velocity at time \( t \) is given by:

\[ v(t) = t^2 - 4t - 5 \]

**Tasks:**

(a) Find the displacement from \( t = 3 \) to \( t = 6 \).

(b) Find the distance traveled from \( t = 3 \) to \( t = 6 \).

**Explanation:**

To find the displacement, integrate the velocity function \( v(t) \) with respect to \( t \) from 3 to 6. Displacement is the net change in position and can be positive, negative, or zero.

For the distance traveled, calculate the integral of the absolute value of the velocity function over the same interval, \( t = 3 \) to \( t = 6 \). Distance is always positive and represents the total path length covered.
Transcribed Image Text:**Velocity and Displacement Analysis** 1. An object is moving along a straight line, and its velocity at time \( t \) is given by: \[ v(t) = t^2 - 4t - 5 \] **Tasks:** (a) Find the displacement from \( t = 3 \) to \( t = 6 \). (b) Find the distance traveled from \( t = 3 \) to \( t = 6 \). **Explanation:** To find the displacement, integrate the velocity function \( v(t) \) with respect to \( t \) from 3 to 6. Displacement is the net change in position and can be positive, negative, or zero. For the distance traveled, calculate the integral of the absolute value of the velocity function over the same interval, \( t = 3 \) to \( t = 6 \). Distance is always positive and represents the total path length covered.
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