1. An investigation is carried out to determine whether face to face or virtual learning is more effective. If 12 students took an IT course virtual and 14 took it face to face: The data of the scores made for both types of learning are shown in the table. Virtual 66 75 85 64 88 77 74 91 72 69 77 83 Face to Face 80 83 64 81 75 80 86 81 51 64 59 85 74 77 Do the following: a) explain the type of data you have here and the hypothesis test you would use to determine the difference between the two types b) determine whether you can conclude that the mean score differs between the two types of course. You need to first set up an alternate and null hypothesis c) construct a pdf for both sets of data and explain the shape of the graph d) calculate a 95% confidence interval for each set of data. e) Determine the error in the sample mean

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Do part d

1. An investigation is carried out to determine whether face to face or virtual learning is more
effective. If 12 students took an IT course virtual and 14 took it face to face: The data of the scores
made for both types of learning are shown in the table.
Virtual
66
75
85
64
88
77
74
91
72
69
77
83
Face to Face
80
83
64
81
75
80
86
81
51
64
59
85
74
77
Do the following:
a) explain the type of data you have here and the hypothesis test you would use to determine the
difference between the two types
b) determine whether you can conclude that the mean score differs between the two types of course.
You need to first set up an alternate and null hypothesis
c) construct a pdf for both sets of data and explain the shape of the graph
d) calculate a 95% confidence interval for each set of data.
e) Determine the error in the sample mean
Transcribed Image Text:1. An investigation is carried out to determine whether face to face or virtual learning is more effective. If 12 students took an IT course virtual and 14 took it face to face: The data of the scores made for both types of learning are shown in the table. Virtual 66 75 85 64 88 77 74 91 72 69 77 83 Face to Face 80 83 64 81 75 80 86 81 51 64 59 85 74 77 Do the following: a) explain the type of data you have here and the hypothesis test you would use to determine the difference between the two types b) determine whether you can conclude that the mean score differs between the two types of course. You need to first set up an alternate and null hypothesis c) construct a pdf for both sets of data and explain the shape of the graph d) calculate a 95% confidence interval for each set of data. e) Determine the error in the sample mean
Expert Solution
Step 1

Given   : 

An investigation is carried out to determine whether face to face or virtual learning is more effective . If 12 student took an IT course virtual and 14 took it face to face . Data represents scores made for both types of learning . 

Find mean and standard deviation for both the sample data : 

For virtual : 

The sample size is n = 12. The provided sample data along with the data required to compute the sample mean \bar X and sample variance s^2 are shown in the table below:

  X X2
  66 4356
  75 5625
  85 7225
  64 4096
  88 7744
  77 5929
  74 5476
  91 8281
  72 5184
  69 4761
  77 5929
  83 6889
Sum = 921 71495

The sample mean \bar X is computed as follows:

Statistics homework question answer, step 1, image 1

 

For face to face : 

The sample size is n = 14. The provided sample data along with the data required to compute the sample mean \bar X and sample variance s^2 are shown in the table below:

  X X2
  80 6400
  83 6889
  64 4096
  81 6561
  75 5625
  80 6400
  86 7396
  81 6561
  51 2601
  64 4096
  59 3481
  85 7225
  74 5476
  77 5929
Sum = 1040 78736

The sample mean is computed as follows: 

Statistics homework question answer, step 1, image 2

 

 

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