1. An e-commerce résearch company claims that 60% or more graduate students have bought merchandise on-line. A consumer group is suspicious of the claim and thinks that the proportion is lower than 60%. A random sample of 80 graduate students show that only 22 students have ever don so. Is there enough evidence to show that the true proportion is lower than 60%? Conduct the test at 10% significance level. Ston 1 E.C

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Chapter1: Combinatorial Analysis
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Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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1. An e-commerce résearch company claims that 60% or more graduate students have bought
merchandise on-line. A consumer group is suspicious of the claim and thinks that the proportion is
lower than 60%. A random sample of 80 graduate students show that only 22 students have ever done
so. Is there enough evidence to show that the true proportion is lower than 60%? Conduct the test at
10% significance level.
Step 1.5: Check the conditions with np >5 and nq > 5 to be sure we can use a normal distribution.
Step 2. State the null hypothesis and alternate hypothesis
From "...enough evidence to show that the true proportion is lower...," we write the alternate
hypothesis
H,: p
Step 3. Identify the statistical test to use and find the test statistic. Use z-test because about
proportions/percent.
H,: p
Find
z =
z =
pq
Step 4:
hand).
Use the online calculator to determine the p-value (after you have found z by
P-value =
Step 5. If the p-value is lower than a, reject the null. If the p-value is greater than a, fail to reject the null
(or accept the null).
Transcribed Image Text:nesis Testing for Proportions Practice E O Format Tools Add-ons Help Last edit was seconds ago Normal text Arial 8 BIUA 中田回▼ 三, 三三▼ 1. An e-commerce résearch company claims that 60% or more graduate students have bought merchandise on-line. A consumer group is suspicious of the claim and thinks that the proportion is lower than 60%. A random sample of 80 graduate students show that only 22 students have ever done so. Is there enough evidence to show that the true proportion is lower than 60%? Conduct the test at 10% significance level. Step 1.5: Check the conditions with np >5 and nq > 5 to be sure we can use a normal distribution. Step 2. State the null hypothesis and alternate hypothesis From "...enough evidence to show that the true proportion is lower...," we write the alternate hypothesis H,: p Step 3. Identify the statistical test to use and find the test statistic. Use z-test because about proportions/percent. H,: p Find z = z = pq Step 4: hand). Use the online calculator to determine the p-value (after you have found z by P-value = Step 5. If the p-value is lower than a, reject the null. If the p-value is greater than a, fail to reject the null (or accept the null).
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