1. An automobile of mass M=5400 kg is moving at a speed of 30 m/s.The engine is disengaged suddenly at t= 0 sec. Assume that the equation of motion after t=0 is given by 5400 vdvdx= -8.276 v2-2000 Where v= v(t) is the speed (m/sec) of the car at t. The left side represents Mv (dv/dx).The first term on the right side is the aerodynamics drag, Mand the second term is the rolling resistance of the tires. Calculate how far the car travels until the speed reduces to 15 m/sec.(hint: the equation of motion may be integrated as 1530 5400 v dv8.276 v2+2000 = dx=x Evaluate the preceding equation using Simpson rule).

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1. An automobile of mass M=5400 kg is moving at a speed of 30 m/s.The engine is
disengaged suddenly at t= 0 sec. Assume that the equation of motion after t=0 is
given by
5400 vdvdx= -8.276 v2-2000
Where v= v(t) is the speed (m/sec) of the car at t. The left side represents Mv
(dv/dx).The first term on the right side is the aerodynamics drag,
||||||||and the second term is the rolling resistance of the tires.
Calculate how far the car travels until the speed reduces to 15 m/sec.(hint: the
equation of motion may be integrated as
1530 5400 v dv8.276 v2+2000 = dx=x
%3D
Evaluate the preceding equation using Simpson rule).
A finction tablo is givon as folloAIC:
Transcribed Image Text:1. An automobile of mass M=5400 kg is moving at a speed of 30 m/s.The engine is disengaged suddenly at t= 0 sec. Assume that the equation of motion after t=0 is given by 5400 vdvdx= -8.276 v2-2000 Where v= v(t) is the speed (m/sec) of the car at t. The left side represents Mv (dv/dx).The first term on the right side is the aerodynamics drag, ||||||||and the second term is the rolling resistance of the tires. Calculate how far the car travels until the speed reduces to 15 m/sec.(hint: the equation of motion may be integrated as 1530 5400 v dv8.276 v2+2000 = dx=x %3D Evaluate the preceding equation using Simpson rule). A finction tablo is givon as folloAIC:
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