1. A test charge of +2μC is placed halfway between a charge of +6μC and another of +4µC separated by distance 2d = 9 cm. +4uC The free body diagram of q2 from Part 1 should look like this: 9₁ = +4µC +2μC F3-2 35.52 q2 = +2 μC N F1-2 +6μС The force on q2 due to q₁ is repulsive and acts to the right. The force on q2 due to q3 is repulsive and acts to the left. F32 F1-2 (b) Calculate the force on the test charge by the +4μC charge. N (c) Calculate the net force on the test charge by both the charges. X because 9391. (a) Calculate the force on the test charge by the +6μC charge. Hint: The force in the positive x-direction is positive and the negative x direction is negative. N 93 = +6 μC

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1. A test charge of +2µC is placed halfway between a charge of +6µC and another of +4µC
separated by distance 2d = 9 cm.
+4uC
The free body diagram of q2 from Part 1 should look like this:
9₁ = +4 µC
d
35.52
+2μC
F3-2
✔N
92 = +2 μC
F₁-2
+6μС X
The force on q2 due to q₁ is repulsive and acts to the right. The force on q2 due to q3 is
repulsive and acts to the left.
F3-2 > F1-2
93 =
because 93 91.
(a) Calculate the force on the test charge by the +6μC charge.
Hint: The force in the positive x-direction is positive and the negative x direction is negative.
✔N
(b) Calculate the force on the test charge by the +4µC charge.
(c) Calculate the net force on the test charge by both the charges.
+6 μC
Transcribed Image Text:1. A test charge of +2µC is placed halfway between a charge of +6µC and another of +4µC separated by distance 2d = 9 cm. +4uC The free body diagram of q2 from Part 1 should look like this: 9₁ = +4 µC d 35.52 +2μC F3-2 ✔N 92 = +2 μC F₁-2 +6μС X The force on q2 due to q₁ is repulsive and acts to the right. The force on q2 due to q3 is repulsive and acts to the left. F3-2 > F1-2 93 = because 93 91. (a) Calculate the force on the test charge by the +6μC charge. Hint: The force in the positive x-direction is positive and the negative x direction is negative. ✔N (b) Calculate the force on the test charge by the +4µC charge. (c) Calculate the net force on the test charge by both the charges. +6 μC
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