1. A student performed this experiment and obtained the following concentration values: 0.02813 M, 0.02802, and 0.02788 M a. what is the mean concentration? b. what is the standard deviation of these results?
1. A student performed this experiment and obtained the following concentration values: 0.02813 M, 0.02802, and 0.02788 M a. what is the mean concentration? b. what is the standard deviation of these results?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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1. A student performed this experiment and obtained the following concentration values: 0.02813 M, 0.02802, and 0.02788 M
a. what is the mean concentration?
b. what is the standard deviation of these results?
3. how would the following errors affect the concentration of Cl- obtained in question 2b? give your reasoning in each case.
a. the student read the molarity of AgNo3 as 0.02104M instead of 0.02014M
b. the student was past the endpoint of titration when he took the final buret reading.
![**Experiment 7**
**Advance Study Assignment:** Analysis of an Unknown Chloride
1. A student performed this experiment and obtained the following concentration values: 0.02813 M, 0.02802 M, and 0.02788 M.
a. What is the mean concentration?
\_\_\_\_\_\_\_\_\_ M
b. What is the standard deviation of these results?
\_\_\_\_\_\_\_\_\_ M
2. A 10.00 mL diluted chloride sample required 13.89 mL of 0.02014 M AgNO₃ to reach the Fajans endpoint.
a. How many moles of Cl⁻ ion were present in the sample? (Use Eqs. 2 and 3.)
\[ \text{moles of Ag⁺} = \text{moles of AgNO₃} \]
\[ 0.02014 M \times 0.01389 L = 0.00028 \text{ moles} \]
\[ 0.00028 \text{ moles Cl}⁻ \]
b. What was the concentration of chloride in the diluted solution?
\[ \]
\[ \text{M₂} = \frac{0.02014 M \times 13.89 mL}{10.00 mL} \]
\[ = \frac{0.28}{10.00} \, M \]
\[ = 0.028 \, M \]
3. How would the following errors affect the concentration of Cl⁻ obtained in Question 2b? Give your reasoning in each case.
a. The student read the molarity of AgNO₃ as 0.02104 M instead of 0.02014 M.
b. The student was past the endpoint of the titration when he took the final buret reading.
**Copyright 2016 Cengage Learning. All Rights Reserved.** May not be copied, scanned, or duplicated, in whole or in part. Due to electronic rights, some third party content may be suppressed from the eBook and/or eChapter(s). Editorial review has deemed that any suppressed content does not materially affect the overall learning experience. Cengage Learning reserves the right to remove additional](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdec5afcc-1b1f-4d8a-a91d-78428b1875fd%2Fbb8f5e94-02e0-422f-b26c-65e8fba6d617%2Fmgvdiz.jpeg&w=3840&q=75)
Transcribed Image Text:**Experiment 7**
**Advance Study Assignment:** Analysis of an Unknown Chloride
1. A student performed this experiment and obtained the following concentration values: 0.02813 M, 0.02802 M, and 0.02788 M.
a. What is the mean concentration?
\_\_\_\_\_\_\_\_\_ M
b. What is the standard deviation of these results?
\_\_\_\_\_\_\_\_\_ M
2. A 10.00 mL diluted chloride sample required 13.89 mL of 0.02014 M AgNO₃ to reach the Fajans endpoint.
a. How many moles of Cl⁻ ion were present in the sample? (Use Eqs. 2 and 3.)
\[ \text{moles of Ag⁺} = \text{moles of AgNO₃} \]
\[ 0.02014 M \times 0.01389 L = 0.00028 \text{ moles} \]
\[ 0.00028 \text{ moles Cl}⁻ \]
b. What was the concentration of chloride in the diluted solution?
\[ \]
\[ \text{M₂} = \frac{0.02014 M \times 13.89 mL}{10.00 mL} \]
\[ = \frac{0.28}{10.00} \, M \]
\[ = 0.028 \, M \]
3. How would the following errors affect the concentration of Cl⁻ obtained in Question 2b? Give your reasoning in each case.
a. The student read the molarity of AgNO₃ as 0.02104 M instead of 0.02014 M.
b. The student was past the endpoint of the titration when he took the final buret reading.
**Copyright 2016 Cengage Learning. All Rights Reserved.** May not be copied, scanned, or duplicated, in whole or in part. Due to electronic rights, some third party content may be suppressed from the eBook and/or eChapter(s). Editorial review has deemed that any suppressed content does not materially affect the overall learning experience. Cengage Learning reserves the right to remove additional
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