1. A string has a partial differential equation with its initial conditions and boundar equation of 8² u Ət² = 9 J²u მ2 u (x,0) = 2x(x-1) du Ət u (0, t) = 0 u (L, t) = 0 Find u(t). -(x,0) = 0

Advanced Engineering Mathematics
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Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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1. A string has a partial differential equation with its initial conditions and boundar
equation of
8² u
Ət²
= 9
J²u
მ2
u (x,0) =
2x(x-1)
du
Ət
u (0, t) = 0 u (L, t) = 0
Find u(t).
-(x,0) = 0
Transcribed Image Text:1. A string has a partial differential equation with its initial conditions and boundar equation of 8² u Ət² = 9 J²u მ2 u (x,0) = 2x(x-1) du Ət u (0, t) = 0 u (L, t) = 0 Find u(t). -(x,0) = 0
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