1. A sphere of surface area 100 m and temperature 500 K radiates 0.2 MW. Calculate: a. The emissivity of the surface. b. The peak wavelength of radiation emitted. C. The intensity at a distance of 100m from the centre. d. The energy absorbed per second by a 2m disc with albedo 0.6 placed with it's plane perpendicular to the direction of the radiation. e. The temperature of the disc when it reaches equilibrium (emissivity of the disc = 1). P= eAoT A = 0.00289/T Page 11 1
1. A sphere of surface area 100 m and temperature 500 K radiates 0.2 MW. Calculate: a. The emissivity of the surface. b. The peak wavelength of radiation emitted. C. The intensity at a distance of 100m from the centre. d. The energy absorbed per second by a 2m disc with albedo 0.6 placed with it's plane perpendicular to the direction of the radiation. e. The temperature of the disc when it reaches equilibrium (emissivity of the disc = 1). P= eAoT A = 0.00289/T Page 11 1
Related questions
Question
![1. A sphere of surface area 100 m and temperature 500 K radiates 0.2 MW. Calculate:
a. The emissivity of the surface.
b. The peak wavelength of radiation emitted.
C. The intensity at a distance of 100m from the centre.
d. The energy absorbed per second by a 2m disc with albedo 0.6 placed with it's plane
perpendicular to the direction of the radiation.
e. The temperature of the disc when it reaches equilibrium (emissivity of the disc = 1).
P= eAoT
A = 0.00289/T
G- 5.67 x 10* Wm°K*
Page 1 1 1
Q +](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F92e106bd-1dbc-40e4-99dc-acce8699c3ae%2F5c2105fd-5355-4bdc-9679-445f51f7e7cd%2Fqsak02f_processed.png&w=3840&q=75)
Transcribed Image Text:1. A sphere of surface area 100 m and temperature 500 K radiates 0.2 MW. Calculate:
a. The emissivity of the surface.
b. The peak wavelength of radiation emitted.
C. The intensity at a distance of 100m from the centre.
d. The energy absorbed per second by a 2m disc with albedo 0.6 placed with it's plane
perpendicular to the direction of the radiation.
e. The temperature of the disc when it reaches equilibrium (emissivity of the disc = 1).
P= eAoT
A = 0.00289/T
G- 5.67 x 10* Wm°K*
Page 1 1 1
Q +
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 3 steps with 2 images
![Blurred answer](/static/compass_v2/solution-images/blurred-answer.jpg)