## Educational Text Transcription### 1. Solution AnalysisA solution contains 480 mg/l of FeCl₃; temperature is 15°C.- **a)** What is the TDS of this solution?- **b)** What is the approximate conductivity of the solution in micromhos/cm?**Remember:**- TDS (Total Dissolved Solids) is the summation of concentration of all the ions in the solution.**Instruction:**Use the equation for the relationship of TDS and Conductivity provided in the slides to calculate the conductivity.### 2. Waterborne Infectious Diseases in the U.S.Historically, in the United States, the prevalent waterborne infectious diseases have been typhoid, cholera, and dysentery. How have these diseases been virtually eliminated? Currently, the prevalent infectious diseases are giardiasis and cryptosporidiosis, causing diarrhea that can be life-threatening for persons with immunodeficiency syndrome. What actions are being taken to reduce the probability of waterborne transmission of these diseases?### 3. COVID-19 and Drinking WaterCan a person be infected with COVID-19 through drinking water?### 4. HIV and Drinking WaterCan a person be infected with HIV through drinking water?

In the solution, ferric chloride () will be dissociated as follows: FeCl3 → Fe3+ + 3Cl- Thus, there will be two ions namely iron ion and chloride ion in the solution. Hence, the total dissolved solids or TDS would be TDS=CFe3+ + CCl- Here, CFe3+ = concentration of iron. CCl- = concentration of chloride ion. The relationship between TDS and the conductivity of the solution is given by TDS=ke×σ .. (2) Here, σ = conductivity of the solution in μohm-1cm-1. ke = proportionality constant, generally ke=0.7.1a) Given that, Concentration of FeCl3 = 480 mg/l. Hence, we can say that Concentration of Fe3+ = 480 mg/l Concentration of Cl- = 480×3=1440 mg/l Hence, according to the TDS equation, we can say TDS=480+1440=1920 mg/l Hence, the TDS of the solution is 1920 milligrams per liter. 1b) According to equation (2), we can write 1920=0.7×σ or, σ=2742.85 μohm-1cm-1 Hence, the approximate conductivity of the solution would be 2742.85 microohm-1cm-1.

Science

Chemistry

1. A solution contains 480 mg/l of FeC13; temperature is 15 C. a) What is the TDS of this solution? b) What is the approximate conductivity of the solution in micromhos/cm? Remember: TDS (Total Dissolved Solids) is the summation of concentration all the ions in the solution. Use the equation for the relationship of TDS and Conductivity in the slides to calculate the conductivity.

1. A solution contains 480 mg/l of FeC13; temperature is 15 C. a) What is the TDS of this solution? b) What is the approximate conductivity of the solution in micromhos/cm? Remember: TDS (Total Dissolved Solids) is the summation of concentration all the ions in the solution. Use the equation for the relationship of TDS and Conductivity in the slides to calculate the conductivity.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

The molar solubility of Pb (103)₂ Be sure your answer has the correct number of significant digits. K₂-1 -0 sp in a 0.21 M NalO3 solution is 3.8 x 10 X 11 mol L What is Ksp for Pb (103)₂?
Consider the following equilibrium: Cu²+ (aq) + 4NH3(aq) Cu(NH3)4²+ (aq) (Kf = 4.8e+12) A solution is made by mixing 15.0 mL of 0.90 M CuSO4 and 1.00 L of 0.530 M NH3. Assume additive volumes to answer the following questions. Give all answers to three sig figs. a) What is the concentration of NH3 in the resulting solution? [NH3] = M b) What is the concentration of Cu(NH3)42+ in the resulting solution? [Cu(NH3)4²+] = M c) What is the concentration of Cu²+ in the resulting solution? [Cu²+] = M
A 1.000-g sample of a sweetening agent containing soluble Saccharin (MM=205.17g/mol) was analyzed using the Volhard method as follows: Step 1: Sample was dissolved in distilled water and treated with 10.0 mL of 0.05M AgNO3. Saccharin-Na + Ag+ → Saccharin-Ag (s) + Na+ Step 2: The solid, Saccharin-Ag (s), formed was filtered off and washed with water. The filtrate and washing were collected quantitatively. Step 3: Titration of the filtrate and washings required 4.6 mL of 0.04M KSCN. KSCN + Ag + → AgSCN (s) + K+ Calculate weight % saccharin in the sweetening agent sample. could you type it out, please
13. Hydroxyapatite is the main mineral component of bone. How many grams of hydroxyapatite will dissolve in 1.00 L of H20? Ksp = 2.34 x 10-59; Molar mass = 502.3 g/mol Cas (PO4)30H (s) 5 Ca2+ (aq) + 3 PO43- (aq) + OH- (aq)
Answer all questions completely. SHOW ALL WORK/CALCULATIONS:
An impure sample of oxalis acid was oxidized by potassium permanganate. A 0.261g sample of oxalis acid was dissolved and the solution was diluted to 100ml. A 25.0 ml portion of the oxalis acid solution was titrated with 26.2ml of 0.0107M potassium permanganate. How many moles of oxalis acid were titrated and what is the percent purity of the oxalis acid sample?
Suppose the Kc value for Cobalt (II) hexahydrate is 6.80 and suppose upon heating the solution turned pink. If a group of student started mixed 10.5 mL of a 1.25 M [Co(H2O)6]2+(aq) solution with 12.5 mL of a 1.55 M solution of NaCl(aq) with 15.25 mL of a 1.39 M [CoCl4]-2(aq) solution then what color is the solution at equilibrium? [Co(H2O)6]2+(aq) + 4 Cl-(aq) [CoCl4]-2(aq) + 6 H2O(L) Multiple choices pink purple green black orange brown blue colorless yellow gray red green
Please help me out with making flowchart with thes steps. Write the result. Procedure 1. Place 20 drops of each of the following aqueous solutions to separate centrifuge tubes: 0.1M Cr (NO3)3, 0.1M Al (NO3)3, 0.1M Co (NO3)2, 0.1M Zn (NO3)2, 0.1M Mn (OH)2, 0.1M Ni (NO3)2, 0.1 M Fe (NO3)3. Make each solution basic by adding few drops of 6M NH4OH. Confirm using a litmus paper. 2. Add 5 drops of freshly prepared 6M (NH4)2S to each centrifuge tube. Place the samples in the centrifuge machine for 3 mins. After centrifuge record results. Decant the supernatant liquid of all the samples. 3. Add one drop of NH4OH in each centrifuge tubes. Add 20 drops of distilled water in each centrifuge tubes. Then add a few drops of 6M HCl in each solution. Place the samples in the water bath for 10 mins. After water bath, centrifuge the samples for 3 mins. 4. After centrifuge, add a few drops of 6M NH4Cl in each sample. Decant the supernatant liquid in each sample. 5. To the centrifuge containing…