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1. A soil profile is shown in the figure.A uniformly distribute d load of 50 Kpa is applied at the ground surface. Assume Cs= 1/5 Cc. What is the settlement of the clay layer caused by primary consolidation if: a. The clay is normally consolidate d b. The preconsolidation pre ssure, de= 210 Kpa c. The preconsolidation pre ssure, o= 150 Kpa Ap = 50 kPa Sand 3 m Yay= 16 kN/m Ground water table to 6 m Sand Ya = 18.5 kN/m Clay 19 kN/m Yur= e = 0.95 LL = 50 8 m Sand Figure 06.4

1. A soil profile is shown in the figure.A uniformly distribute d load of 50 Kpa is applied at the ground surface. Assume Cs= 1/5 Cc. What is the settlement of the clay layer caused by primary consolidation if: a. The clay is normally consolidate d b. The preconsolidation pre ssure, de= 210 Kpa c. The preconsolidation pre ssure, o= 150 Kpa Ap = 50 kPa Sand 3 m Yay= 16 kN/m Ground water table to 6 m Sand Ya = 18.5 kN/m Clay 19 kN/m Yur= e = 0.95 LL = 50 8 m Sand Figure 06.4

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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1. A soil profile is shown in the figure.A uniformly distribute d load of 50 Kpa is applied at the ground surface. Assume Cs= 1/5 Cc. What is the settlement of the clay layercaused by primary consolidation if: a. The clay is normally consolidate d b. The preconsolidation pre ssure, de= 210 Kpa c. The preconsolidation pressure, o.= 150 Kpa Ap = 50 kPa Sand 3 m Yay = 16 kN/m? Ground water table 6 m Sand Ya = 18.5 kN/m Clay Yar = 19 kN/m e = 0.95 LL = 50 8 m Sand Figure 06.4
Transcribed Image Text:1. A soil profile is shown in the figure.A uniformly distribute d load of 50 Kpa is applied at the ground surface. Assume Cs= 1/5 Cc. What is the settlement of the clay layercaused by primary consolidation if: a. The clay is normally consolidate d b. The preconsolidation pre ssure, de= 210 Kpa c. The preconsolidation pressure, o.= 150 Kpa Ap = 50 kPa Sand 3 m Yay = 16 kN/m? Ground water table 6 m Sand Ya = 18.5 kN/m Clay Yar = 19 kN/m e = 0.95 LL = 50 8 m Sand Figure 06.4
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