1.A simple inverter imposes a square wave on a load. Filtering is accomplished by including a se-ries 25 mH inductor at the output. The load resembles a resistor. Given a 50 Hz circuit applica-tion, plot the amplitude of the wanted component of the output voltage as a function of the loadresistance in this case. Comment on load regulation.

Answered: 1. A simple inverter imposes a square…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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The load voltage waveform of a single phase full bridge inverter supplied from 300V DC voltage source is shown in below figure. Output frequency is 50HZ and the load consists of series R-L components. The load values are 20 and 0.04H, respectively. (Conduction interval for half period is 120°) 150 100 50 T -50 -100 -150 .002 .004 .006 .008 .01 .012 .014 .016 .018 .02 Time (sec) a. Calculate and draw the load current for the first two-period interval b. Calculate and draw the load current for the steady-state condition c. Find the RMS values of the load voltage and the load current d. Calculate and draw the voltage across the load inductance Calculate and draw the source current and find its average value e.
A full-bridge inverter has a switching sequence that produces a square wave voltage across a series RL load. The switching frequency is 60 Hz, Vdc=100 V, R equals to 10 Ohm, and L equals 25 mH. The average current in the dc source is. Select one: O a. 52 A O b. None of the above O c. 4.41 A O d. 300 A
Simulation is NOT required. Please show calculations please. Thank you.
2) A single-phase full-bridge inverter has a DC voltage source V = 230 V. The rms value of the fundamental component of the output voltage is a- 90 V. b- 207 V. C- 350 V. d- 196 V.
Q5. A general analysis of the switch-mode inverter shown in the figure below is to be done. The switching frequency f,, which is also the frequency of the triangular signal is 1450 Hz. The de voltage, Va, is 600 V. Output voltage is sinusoidal voltage with a frequency equal to 50 Hz. TA ADA. TA- ADA- VAN (Figure 8-4 on page 203 from Mohan's Book) a. Find the frequency modulation ratio, mr. b. Why the frequency modulation is chosen as an integer? c. Calculate the output voltage (rms value of first harmonic), when the amplitude modulation ratio, m., is equal to 0.8. d. Compute the rms values of the 5 most dominant harmonics of v4o at m,=0.8. e. Also indicate the frequencies at these harmonics you have found in part d appear.
I need to solve it quickly
A full-bridge inverter has a switching sequence that produces a square wave voltage across a series RL load. The switching frequency is 60 Hz, Vdc=100 V, R10=Ohm, and L= 25 mH. The power absorbed by the load is. Select one: O a. None of the above O b. 1500 W O c. 1000 W O d. 441 W
A square-wave inverter has an R-L load with R = 15 N and L = 10 mH. The inverter output frequency is 400 Hz 1. Determine the value of the de source required to establish a load current which has a fundamental frequency component of 10 A rms. (b) Determine the THD of the load current. (c) Sketch the output and input currents. (a)
A single phase inverter has square wave output voltage. What is the percentage of the fifth harmonic component in relation to the fundamental component ?
A single phase full-bridge inverter is supplying a series RL load (R=25Q, L=0.05H) from a 250V DC source. The full square-wave output waveform period is 8ms. The controlled switches are IGBTS. Assume the circuit is ideal. a. Sketch the scaled load current for first two periods from starting by calculating. (Assuming i=0 at =0) b. For steady state operation find the maximum and minimum values of load current. c. Calculate the IGBT conduction time. d. Calculate the diode conduction time. e. Sketch the scaled voltage across the load inductance. f. Calculate the mean value of the source current.
One half bridge inverter with bidirectional switches and one full bridge inverter with bidirectional switches are connected to similar loads (R=102) and providing both an output power of 1 KW. The rms transistor currents of the half bridge and full bridge inverters are respectively: Select one: O a. 5A, 7.07A O b. 5A, 5A O c. 7.07A, 5A Od. None of these
The output voltage and current wave forms of single phase full bridge voltage source inverter with R - L load is shown. Where R = 2002, L = 0.2H. It is operated without PWM and fs = 100 Hz. The zero crossing instant is (a) 1.63 ms (b) 2.19 ms (c) 2.25 ms (d) 2.72 ms M +400V -400V

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