1. A simple curve has a central angle of 36' and a degree of curve of 6". (a) Find the nearest distano from the midpoint of the curve to the point of intersection of the tangents, (b) Compute th distance from the midpoint of the curve to the midpoint of the long chord joining the point a tangency and point of curvature, and (c) If the stationing of the point of curvature is 10+020 compute the stationing on the curve which intersects with the line making a deflection angle o 8' with the tangent through the PC.

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
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7:28
Activity No.1
1. A simple curve has a central angle of 36' and a degree of curve of 6". (a) Find the nearest distance
from the midpoint of the curve to the point of intersection of the tangents, (b) Compute the
distance from the midpoint of the curve to the midpoint of the long chord joining the point of
tangency and point of curvature, and (c) If the stationing of the point of curvature is 10+020,
compute the stationing on the curve which intersects with the line making a deflection angle of
8' with the tangent through the PC.
2. The tangent through the PC has a direction due north and the tangent through the PT has a
bearing of N50'E. It has a radius of 200m. Station of the PC is 12+060. (a) Compute the tangent
distance of the curve, (b) Compute the long chord of the curve, and (c) If the line making an angle
of 62' with the tangent through the PC intersects the curve at point B, what is the stationing of B
if this line passes through the center of the curve.
3. Two tangents making an angle of 62" from each other is connected by a simple curve. A pint X on
the curve is located by a distance along the tangent from the PC equal to 240m and an offset from
the tangent equal to 60m. The PC is at station 10+080. (a) Compute the radius of the curve, (b)
Compute the tangent distance of the curve, and (c) Compute the stationing of point X on the
curve.
4. A simple curve having a radius of 229.18m has a back tangent of N28°E and a forward tangent of
N66°E. A property line running parallel to the back tangent crosses the curve at a distance of 10Om
from it. If the PC of the curve is at 10+120.6. (a) What is the deflection angle at the point of
intersection of the property line and the curve measured from the tangent at station 10+120.6,
(b) What is the stationing at the point of intersection of the property line and the curve, and (c)
Compute the chord distance from the PC to the point of intersection of the property line and the
curve?
5. The offset distance from PC to PT of a simple curve is 18m and the angle of intersection of the
tangents is 24', If the stationing of PT is 45+158.32, (a) what is the stationing of the PI, and (b)
compute the area enclosed by the curve.
6. A5' curve intersects a property line CD at point D. The back tangent intersects the property line
at C which is 105.27m from the PC that is at station 2+040. The angle that the property line CD
makes with the back tangent is 110'50'. (a) Determine the distance CD, (b) Determine the
stationing of point D, and (c) Determine the deflection angle of point D from the PC.
7. A simple curve is laid out from lines AB and VC whose azimuths are 220'45' and 257 25',
respectively. A Vv'K line (point V' on the tangent and point K on the curve) crosses the curve on the
side of the forward tangent 35.2m from point V. The stationing of the V is at 10+283.68 and the
external distance of the curve is 10.2m. (a) Compute the radius of the curve, (b) Compute the
stationing at PT, and (c) Compute the stationing of point K.
Transcribed Image Text:7:28 Activity No.1 1. A simple curve has a central angle of 36' and a degree of curve of 6". (a) Find the nearest distance from the midpoint of the curve to the point of intersection of the tangents, (b) Compute the distance from the midpoint of the curve to the midpoint of the long chord joining the point of tangency and point of curvature, and (c) If the stationing of the point of curvature is 10+020, compute the stationing on the curve which intersects with the line making a deflection angle of 8' with the tangent through the PC. 2. The tangent through the PC has a direction due north and the tangent through the PT has a bearing of N50'E. It has a radius of 200m. Station of the PC is 12+060. (a) Compute the tangent distance of the curve, (b) Compute the long chord of the curve, and (c) If the line making an angle of 62' with the tangent through the PC intersects the curve at point B, what is the stationing of B if this line passes through the center of the curve. 3. Two tangents making an angle of 62" from each other is connected by a simple curve. A pint X on the curve is located by a distance along the tangent from the PC equal to 240m and an offset from the tangent equal to 60m. The PC is at station 10+080. (a) Compute the radius of the curve, (b) Compute the tangent distance of the curve, and (c) Compute the stationing of point X on the curve. 4. A simple curve having a radius of 229.18m has a back tangent of N28°E and a forward tangent of N66°E. A property line running parallel to the back tangent crosses the curve at a distance of 10Om from it. If the PC of the curve is at 10+120.6. (a) What is the deflection angle at the point of intersection of the property line and the curve measured from the tangent at station 10+120.6, (b) What is the stationing at the point of intersection of the property line and the curve, and (c) Compute the chord distance from the PC to the point of intersection of the property line and the curve? 5. The offset distance from PC to PT of a simple curve is 18m and the angle of intersection of the tangents is 24', If the stationing of PT is 45+158.32, (a) what is the stationing of the PI, and (b) compute the area enclosed by the curve. 6. A5' curve intersects a property line CD at point D. The back tangent intersects the property line at C which is 105.27m from the PC that is at station 2+040. The angle that the property line CD makes with the back tangent is 110'50'. (a) Determine the distance CD, (b) Determine the stationing of point D, and (c) Determine the deflection angle of point D from the PC. 7. A simple curve is laid out from lines AB and VC whose azimuths are 220'45' and 257 25', respectively. A Vv'K line (point V' on the tangent and point K on the curve) crosses the curve on the side of the forward tangent 35.2m from point V. The stationing of the V is at 10+283.68 and the external distance of the curve is 10.2m. (a) Compute the radius of the curve, (b) Compute the stationing at PT, and (c) Compute the stationing of point K.
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