1. A satellite of mass M moves around the Earth in a circular orbit of radius R. The orbital period of the satellite is T. A second satellite of mass 3M is also moving around the Earth in a circular orbit of radius R. The orbital period of the second satellite is (a) 3T (b) T/3 (c) T (d) 97 (e) T/9
1. A satellite of mass M moves around the Earth in a circular orbit of radius R. The orbital period of the satellite is T. A second satellite of mass 3M is also moving around the Earth in a circular orbit of radius R. The orbital period of the second satellite is (a) 3T (b) T/3 (c) T (d) 97 (e) T/9
Principles of Physics: A Calculus-Based Text
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Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter11: Gravity, Planetary Orbits, And The Hydrogen Atom
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![**Problem: Satellite Orbital Period**
1. A satellite of mass \( M \) moves around the Earth in a circular orbit of radius \( R \). The orbital period of the satellite is \( T \). A second satellite of mass \( 3M \) is also moving around the Earth in a circular orbit of radius \( R \). The orbital period of the second satellite is:
(a) \( 3T \)
(b) \( T/3 \)
(c) \( T \)
(d) \( 9T \)
(e) \( T/9 \)
---
#### Explanation:
This problem involves an understanding of satellite motion, specifically the relationship between the mass of a satellite, its orbital radius, and its orbital period. The key concept to recall here is Kepler's third law which enables us to relate these aspects.
**Concept:**
Kepler's third law states that the orbital period \( T \) of a satellite around a planet is related to the radius \( R \) of its orbit by the equation:
\[ T^2 \propto R^3 \]
Interestingly, the orbital period is independent of the mass of the satellite. Therefore, the orbital periods of satellites in the same orbit (with the same radius \( R \)) remain the same regardless of their masses.
**Given:**
- First satellite has mass \( M \)
- Orbital radius \( R \)
- Orbital period \( T \)
- Second satellite has mass \( 3M \)
- Orbital radius \( R \)
**Solution:**
Since the orbital period \( T \) only depends on the radius \( R \) according to Kepler's third law, the orbital period of the second satellite will also be \( T \).
**Answer: (c) \( T \)**
This explanation and step-by-step approach help students to understand that the mass of the satellite does not affect the orbital period for a given orbital radius.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbe5243c1-65b6-49ba-aa5b-abca4f72257e%2Fd0242c11-8f15-49bb-9269-d420a06a7107%2Fbo1j4t_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem: Satellite Orbital Period**
1. A satellite of mass \( M \) moves around the Earth in a circular orbit of radius \( R \). The orbital period of the satellite is \( T \). A second satellite of mass \( 3M \) is also moving around the Earth in a circular orbit of radius \( R \). The orbital period of the second satellite is:
(a) \( 3T \)
(b) \( T/3 \)
(c) \( T \)
(d) \( 9T \)
(e) \( T/9 \)
---
#### Explanation:
This problem involves an understanding of satellite motion, specifically the relationship between the mass of a satellite, its orbital radius, and its orbital period. The key concept to recall here is Kepler's third law which enables us to relate these aspects.
**Concept:**
Kepler's third law states that the orbital period \( T \) of a satellite around a planet is related to the radius \( R \) of its orbit by the equation:
\[ T^2 \propto R^3 \]
Interestingly, the orbital period is independent of the mass of the satellite. Therefore, the orbital periods of satellites in the same orbit (with the same radius \( R \)) remain the same regardless of their masses.
**Given:**
- First satellite has mass \( M \)
- Orbital radius \( R \)
- Orbital period \( T \)
- Second satellite has mass \( 3M \)
- Orbital radius \( R \)
**Solution:**
Since the orbital period \( T \) only depends on the radius \( R \) according to Kepler's third law, the orbital period of the second satellite will also be \( T \).
**Answer: (c) \( T \)**
This explanation and step-by-step approach help students to understand that the mass of the satellite does not affect the orbital period for a given orbital radius.
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