1. A reversible reaction has reached a state of dynamic chemical equilibrlum. What does this infomation tell you about the rate of formation of products and reactants and how the totalamount of reactants and products? 2. Write the Kag expression for each of the following reactions: a. 2HS (g) + 2H2 (g) + S2 (g) b. CO (g) + HO (g) He (g) + CO2 (g) c. NO4 (g) + 2NO2 (g) d. CO (g)+ 3H2 (g) + CHa (g) + H0 (g) 3. For each of the equilibrium constants given below, Indicate whether the reactants or products are favoured. a. Ke = 3.047 %3! b. Keg = 9.7 x 10 c. Ke = 1.2 × 10 d. Ke = 0.536 4. Comment on the favourablility of product formation in each of these reactions (moderately favourable, moderately unfavourable, slightly favourable, slightly unfavourable, highly favourable or highly unfavourable): a. CO: (g)+ H2 (g) → CO (g) + H¿O (g) Keg = 4.9 x 10s b. CaHa (g) + H2 (g) ++ C2Ho (g). C. 2 NO (g) +2 H2 (g) N2 (g) + 2 H20 (g Ke d. 20, (g)+30, (g). Keg = 0.99 6.5x 10? K = 2.0 x 1057

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Chapter12: Chemical Kinetics
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please help answer questions 1-4 on paper thank you and this about kinetics and equilibrium unit
1. A reversible reaction has reached a state of dynamic chemical
equilibrlum. What does this information tell you about the rate of formation of products
and reactants and how the totalamount of reactants and products?
2. Write the Keg expression for each of the following reactions:
a. 2HS (g) + 2H2 (g) + S2 (g)
b. CO (g) + HO (g)He (g) + CO2 (g)
c. NOa (g) + 2NO2 (g)
d. CO (g)+ 3H2 (g) + CHa (g) + H0 (g)
3. For each of the equilibrium constants given below, Indicate whether the reactants or
products are favoured.
a. Ke = 3.047
%3!
b. Keg = 9.7 x 10
c. Ke = 1.2 × 10
d. Ke = 0.536
4. Comment on the favourablility of product formation in each of these
reactions (moderately favourable, moderately unfavourable, slightly favourable, slightly
unfavourable, highly favourable or highly unfavourable):
a. CO: (g)+ H2 (g) + CO (g) + H¿O (g)
Keg = 4.9 x 10s
b. CaHa (g) + H2 (g)++ C;Ho (g)
Keg = 0.99
c. 2 NO (g)+2 H2 (g) N2 (g) + 2 H2O (g Ke
d. 20, (g)+30, (g).
6.5x 10?
K = 2.0 x 1057
Transcribed Image Text:1. A reversible reaction has reached a state of dynamic chemical equilibrlum. What does this information tell you about the rate of formation of products and reactants and how the totalamount of reactants and products? 2. Write the Keg expression for each of the following reactions: a. 2HS (g) + 2H2 (g) + S2 (g) b. CO (g) + HO (g)He (g) + CO2 (g) c. NOa (g) + 2NO2 (g) d. CO (g)+ 3H2 (g) + CHa (g) + H0 (g) 3. For each of the equilibrium constants given below, Indicate whether the reactants or products are favoured. a. Ke = 3.047 %3! b. Keg = 9.7 x 10 c. Ke = 1.2 × 10 d. Ke = 0.536 4. Comment on the favourablility of product formation in each of these reactions (moderately favourable, moderately unfavourable, slightly favourable, slightly unfavourable, highly favourable or highly unfavourable): a. CO: (g)+ H2 (g) + CO (g) + H¿O (g) Keg = 4.9 x 10s b. CaHa (g) + H2 (g)++ C;Ho (g) Keg = 0.99 c. 2 NO (g)+2 H2 (g) N2 (g) + 2 H2O (g Ke d. 20, (g)+30, (g). 6.5x 10? K = 2.0 x 1057
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