1. A reversible reaction has reached a state of dynamic chemical equilibrlum. What does this infomation tell you about the rate of formation of products and reactants and how the totalamount of reactants and products? 2. Write the Kag expression for each of the following reactions: a. 2HS (g) + 2H2 (g) + S2 (g) b. CO (g) + HO (g) He (g) + CO2 (g) c. NO4 (g) + 2NO2 (g) d. CO (g)+ 3H2 (g) + CHa (g) + H0 (g) 3. For each of the equilibrium constants given below, Indicate whether the reactants or products are favoured. a. Ke = 3.047 %3! b. Keg = 9.7 x 10 c. Ke = 1.2 × 10 d. Ke = 0.536 4. Comment on the favourablility of product formation in each of these reactions (moderately favourable, moderately unfavourable, slightly favourable, slightly unfavourable, highly favourable or highly unfavourable): a. CO: (g)+ H2 (g) → CO (g) + H¿O (g) Keg = 4.9 x 10s b. CaHa (g) + H2 (g) ++ C2Ho (g). C. 2 NO (g) +2 H2 (g) N2 (g) + 2 H20 (g Ke d. 20, (g)+30, (g). Keg = 0.99 6.5x 10? K = 2.0 x 1057
1. A reversible reaction has reached a state of dynamic chemical equilibrlum. What does this infomation tell you about the rate of formation of products and reactants and how the totalamount of reactants and products? 2. Write the Kag expression for each of the following reactions: a. 2HS (g) + 2H2 (g) + S2 (g) b. CO (g) + HO (g) He (g) + CO2 (g) c. NO4 (g) + 2NO2 (g) d. CO (g)+ 3H2 (g) + CHa (g) + H0 (g) 3. For each of the equilibrium constants given below, Indicate whether the reactants or products are favoured. a. Ke = 3.047 %3! b. Keg = 9.7 x 10 c. Ke = 1.2 × 10 d. Ke = 0.536 4. Comment on the favourablility of product formation in each of these reactions (moderately favourable, moderately unfavourable, slightly favourable, slightly unfavourable, highly favourable or highly unfavourable): a. CO: (g)+ H2 (g) → CO (g) + H¿O (g) Keg = 4.9 x 10s b. CaHa (g) + H2 (g) ++ C2Ho (g). C. 2 NO (g) +2 H2 (g) N2 (g) + 2 H20 (g Ke d. 20, (g)+30, (g). Keg = 0.99 6.5x 10? K = 2.0 x 1057
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter12: Chemical Kinetics
Section: Chapter Questions
Problem 5ALQ: Consider the following statements: In general, the rate of a chemical reaction increases a bit at...
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please help answer questions 1-4 on paper thank you and this about kinetics and equilibrium unit
![1. A reversible reaction has reached a state of dynamic chemical
equilibrlum. What does this information tell you about the rate of formation of products
and reactants and how the totalamount of reactants and products?
2. Write the Keg expression for each of the following reactions:
a. 2HS (g) + 2H2 (g) + S2 (g)
b. CO (g) + HO (g)He (g) + CO2 (g)
c. NOa (g) + 2NO2 (g)
d. CO (g)+ 3H2 (g) + CHa (g) + H0 (g)
3. For each of the equilibrium constants given below, Indicate whether the reactants or
products are favoured.
a. Ke = 3.047
%3!
b. Keg = 9.7 x 10
c. Ke = 1.2 × 10
d. Ke = 0.536
4. Comment on the favourablility of product formation in each of these
reactions (moderately favourable, moderately unfavourable, slightly favourable, slightly
unfavourable, highly favourable or highly unfavourable):
a. CO: (g)+ H2 (g) + CO (g) + H¿O (g)
Keg = 4.9 x 10s
b. CaHa (g) + H2 (g)++ C;Ho (g)
Keg = 0.99
c. 2 NO (g)+2 H2 (g) N2 (g) + 2 H2O (g Ke
d. 20, (g)+30, (g).
6.5x 10?
K = 2.0 x 1057](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F924eceec-b61f-4e0e-ac19-069b52d93b97%2F086226ba-c331-46f4-b9e8-e6a516480485%2Flmy6u4g_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1. A reversible reaction has reached a state of dynamic chemical
equilibrlum. What does this information tell you about the rate of formation of products
and reactants and how the totalamount of reactants and products?
2. Write the Keg expression for each of the following reactions:
a. 2HS (g) + 2H2 (g) + S2 (g)
b. CO (g) + HO (g)He (g) + CO2 (g)
c. NOa (g) + 2NO2 (g)
d. CO (g)+ 3H2 (g) + CHa (g) + H0 (g)
3. For each of the equilibrium constants given below, Indicate whether the reactants or
products are favoured.
a. Ke = 3.047
%3!
b. Keg = 9.7 x 10
c. Ke = 1.2 × 10
d. Ke = 0.536
4. Comment on the favourablility of product formation in each of these
reactions (moderately favourable, moderately unfavourable, slightly favourable, slightly
unfavourable, highly favourable or highly unfavourable):
a. CO: (g)+ H2 (g) + CO (g) + H¿O (g)
Keg = 4.9 x 10s
b. CaHa (g) + H2 (g)++ C;Ho (g)
Keg = 0.99
c. 2 NO (g)+2 H2 (g) N2 (g) + 2 H2O (g Ke
d. 20, (g)+30, (g).
6.5x 10?
K = 2.0 x 1057
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