1. A quadrilateral ABCD has masses 1,2,3 and 4 units located at its vertices A(-1,-2, 2), B(3,2,-1), C(1,-2,4) and D(3,1,2). Find the coordinates of the C.M. [(2,0,2)]

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PRACTICE PROBLEMS
A quadrilateral ABCD has masses 1,2,3 and 4 units lócated at its vertices A(-1,-2,
2), B(3,2,-1), C(1,-2,4) and D(3,1,2). Find the coordinates of the C.M. [(2,0,2)]
2. Three particles of masses 2,1,3 respectively have position vectors = 5tî-
2t2j + (3t – 2)k , 2= (2t – 3)î + (12 – 5t²)ĵ + (4 + 6t – 3t3)k, 3 = (2t – 1)î –
(t2 + 2)î – t3k, where t is the time. Find (a) the velocity of C.M. at time t=1 and
(b) the total linear momentum of the system at time t=1. [(a) 3î – 4ĵ – k, (b)
181- 12j- 6k.]
1.
Find the impulse developed by a force given by F = 4tî + (6t2 – 2)ĵ + 12k from
t=0 to t=2. [8î + 12ĵ + 24k]
3.
4.
A particle of unit mass moves in a force field given by F = (3t² – 4t)î + (12t –
6)î + (6t – 12t²)k wheret is the time.
a) Find the change in momentum of the particle from t=1 to t=2. [î + 12ĵ – 19k]
b) If the velocity at t=1 is 4î– 5ĵ + 10k, what is the velocity at t=2? [5i + 7j -9k]
Dr Pragati Ashdhir, Associate Professor, Department of Physics, Hindu College
Transcribed Image Text:THI A mana KI SHAT ProhEALT ms.microsoft.com/_#/pdf/viewer/teams/https:-2F-2Fhinducollegedelhi.sharepoint.com-2Fsites-2FB.Sc.HPhysicsadmission2021-24copy-2F... Q Search PRACTICE PROBLEMS A quadrilateral ABCD has masses 1,2,3 and 4 units lócated at its vertices A(-1,-2, 2), B(3,2,-1), C(1,-2,4) and D(3,1,2). Find the coordinates of the C.M. [(2,0,2)] 2. Three particles of masses 2,1,3 respectively have position vectors = 5tî- 2t2j + (3t – 2)k , 2= (2t – 3)î + (12 – 5t²)ĵ + (4 + 6t – 3t3)k, 3 = (2t – 1)î – (t2 + 2)î – t3k, where t is the time. Find (a) the velocity of C.M. at time t=1 and (b) the total linear momentum of the system at time t=1. [(a) 3î – 4ĵ – k, (b) 181- 12j- 6k.] 1. Find the impulse developed by a force given by F = 4tî + (6t2 – 2)ĵ + 12k from t=0 to t=2. [8î + 12ĵ + 24k] 3. 4. A particle of unit mass moves in a force field given by F = (3t² – 4t)î + (12t – 6)î + (6t – 12t²)k wheret is the time. a) Find the change in momentum of the particle from t=1 to t=2. [î + 12ĵ – 19k] b) If the velocity at t=1 is 4î– 5ĵ + 10k, what is the velocity at t=2? [5i + 7j -9k] Dr Pragati Ashdhir, Associate Professor, Department of Physics, Hindu College
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