1. A piece of iron weighing 72.4g is heated to 100.0°C and plunged into 100.0g water that is initially at 10.0°C in a coffee cup calorimeter. Calculate the final temperature that is reached. Swater = 4.184 J/g°C; SFe = 0.449J/gºC. a. What is the question asking for? b. What information is given? c. Make a sketch of what is happening in this problem. d. What equation(s) will you use? e. Solve it!

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**Title: Calculating Final Temperature in a Calorimetry Experiment**

**Problem Statement:**

A piece of iron weighing 72.4g is heated to 100.0°C and plunged into 100.0g of water that is initially at 10.0°C in a coffee cup calorimeter. Calculate the final temperature that is reached. The specific heat capacities are:  
- Water (\(S_{\text{water}}\)) = 4.184 J/g°C  
- Iron (\(S_{\text{Fe}}\)) = 0.449 J/g°C  

**Questions to Consider:**

a. **What is the question asking for?**
   - The final equilibrium temperature after the iron is submerged in the water.

b. **What information is given?**
   - Mass of iron: 72.4g
   - Initial temperature of iron: 100.0°C
   - Mass of water: 100.0g
   - Initial temperature of water: 10.0°C
   - \(S_{\text{water}}\): 4.184 J/g°C
   - \(S_{\text{Fe}}\): 0.449 J/g°C

c. **Make a sketch of what is happening in this problem.**
   - Visualize a piece of iron being submerged in a cup of water.
   - The heat from the iron transfers to the water until thermal equilibrium is reached.

d. **What equation(s) will you use?**
   - Use the principle of conservation of energy (heat lost by iron = heat gained by water).

e. **Solve it!**
   - Set up the equation:  
     \[(m_{\text{Fe}} \cdot S_{\text{Fe}} \cdot (T_{\text{final}} - T_{\text{initial,Fe}})) = -(m_{\text{water}} \cdot S_{\text{water}} \cdot (T_{\text{final}} - T_{\text{initial,water}}))\]
   - Substitute the given values and solve for \(T_{\text{final}}\).
Transcribed Image Text:**Title: Calculating Final Temperature in a Calorimetry Experiment** **Problem Statement:** A piece of iron weighing 72.4g is heated to 100.0°C and plunged into 100.0g of water that is initially at 10.0°C in a coffee cup calorimeter. Calculate the final temperature that is reached. The specific heat capacities are: - Water (\(S_{\text{water}}\)) = 4.184 J/g°C - Iron (\(S_{\text{Fe}}\)) = 0.449 J/g°C **Questions to Consider:** a. **What is the question asking for?** - The final equilibrium temperature after the iron is submerged in the water. b. **What information is given?** - Mass of iron: 72.4g - Initial temperature of iron: 100.0°C - Mass of water: 100.0g - Initial temperature of water: 10.0°C - \(S_{\text{water}}\): 4.184 J/g°C - \(S_{\text{Fe}}\): 0.449 J/g°C c. **Make a sketch of what is happening in this problem.** - Visualize a piece of iron being submerged in a cup of water. - The heat from the iron transfers to the water until thermal equilibrium is reached. d. **What equation(s) will you use?** - Use the principle of conservation of energy (heat lost by iron = heat gained by water). e. **Solve it!** - Set up the equation: \[(m_{\text{Fe}} \cdot S_{\text{Fe}} \cdot (T_{\text{final}} - T_{\text{initial,Fe}})) = -(m_{\text{water}} \cdot S_{\text{water}} \cdot (T_{\text{final}} - T_{\text{initial,water}}))\] - Substitute the given values and solve for \(T_{\text{final}}\).
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