1. A horizontal curve (curve length = 730.00 ft) connects a tangent segment aligned with a S62°15'30"E bearing to a tangent segment with a S18°20'30"W bearing. Calculate the curve data, and draw a labeled sketch of the curve. Assume the PC is at station 20+25.30. Determine the station of the PI and the PT.
1. A horizontal curve (curve length = 730.00 ft) connects a tangent segment aligned with a S62°15'30"E bearing to a tangent segment with a S18°20'30"W bearing. Calculate the curve data, and draw a labeled sketch of the curve. Assume the PC is at station 20+25.30. Determine the station of the PI and the PT.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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please expain the bearing calculation to feet
![1. A horizontal curve (curve length = 730.00 ft) connects a tangent segment aligned
with a S62°15'30"E bearing to a tangent segment with a S18°20'30"W bearing.
Calculate the curve data, and draw a labeled sketch of the curve. Assume the PC is at
station 20+25.30. Determine the station of the PI and the PT.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7e73dffa-f7e2-4ec8-9d84-4f1c73b1a496%2F75115830-8158-4951-aaee-22f40556c719%2F2cmriyf_processed.png&w=3840&q=75)
Transcribed Image Text:1. A horizontal curve (curve length = 730.00 ft) connects a tangent segment aligned
with a S62°15'30"E bearing to a tangent segment with a S18°20'30"W bearing.
Calculate the curve data, and draw a labeled sketch of the curve. Assume the PC is at
station 20+25.30. Determine the station of the PI and the PT.
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