1. A homozygous recessive genotype for the gene that encodes phenylalanine hydroxylase (which breaks down the amino acid phenylalanine) causes lighter skin color, a musty odor, differences in intellectual development, and seizures. 2. In pea plants, alleles of Gene W control flower color, with the dominant allele (W) leading to purple flower color, and the recessive allele (w) leading to white flower color. Usually, a genotype of WW or Ww leads to purple flowers. However, when Gene C is homozygous recessive, WW or Ww plants always have white flowers. 3. In mallard ducks, feather coloring is controlled by Gene F. A dominant allele (F) leads to green head feathers, while a recessive allele (f) leads to brown head feathers. In male mallards, inheritance of one or more F alleles always leads to the green head feather trait. But female mallards always have brown head feathers, regardless of whether they hay are FF, Ff, or ff. a) Multigene (or polygenic) inheritance b) Epistasis c) Pleiotropy d) Sex-limited inheritance e) Sex-influenced inheritance f) Genetic anticipation g) Lethal allele

1. A homozygous recessive genotype for the gene that encodes phenylalanine hydroxylase (which breaks down the amino acid phenylalanine) causes lighter skin color, a musty odor, differences in intellectual development, and seizures. 2. In pea plants, alleles of Gene W control flower color, with the dominant allele (W) leading to purple flower color, and the recessive allele (w) leading to white flower color. Usually, a genotype of WW or Ww leads to purple flowers. However, when Gene C is homozygous recessive, WW or Ww plants always have white flowers. 3. In mallard ducks, feather coloring is controlled by Gene F. A dominant allele (F) leads to green head feathers, while a recessive allele (f) leads to brown head feathers. In male mallards, inheritance of one or more F alleles always leads to the green head feather trait. But female mallards always have brown head feathers, regardless of whether they hay are FF, Ff, or ff. a) Multigene (or polygenic) inheritance b) Epistasis c) Pleiotropy d) Sex-limited inheritance e) Sex-influenced inheritance f) Genetic anticipation g) Lethal allele

Human Anatomy & Physiology (11th Edition)

11th Edition

ISBN:9780134580999

Author:Elaine N. Marieb, Katja N. Hoehn

Publisher:Elaine N. Marieb, Katja N. Hoehn

Chapter1: The Human Body: An Orientation

Section: Chapter Questions

Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...

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3. One parent is homozygous for the allele for myostatin that results in big muscles and the other parent is heterozygous (MM x Mm). a. Part A (fill in the boxes): M м M m b. Part B (fill in the boxes): Total number of offspring with the heavily muscled phenotype Proportion and percent of heavily muscled offspring Total number of offspring with the in-between phenotype Proportion and percent of in-between offspring Total number of offspring with typical muscles Proportion and percent of typical muscled offspring Total: 100%
1. In man, normal color vision vs. red green colorblindness is controlled by C (dominant) and c (recessive) at an X-linked locus. a. Can a normal daughter have a color-blind father? A normal father? A color-blind mother? A normal mother? b. Can two normal parents have a color-blind son? A color-blind daughter? c. Can two color-blind parents have a normal daughter? A normal son?
1. An albino man whose parents are both normal marries a woman one of whose parents is normal and the other albino. She has an albino sister. The couple has a normal son. a. Is albinism a dominant or a recessive trait? Explain your answer. b. Give the genotypes of all the persons involved. c.The couple plans to have more kids. What is the probability of their second child being normal?
3. Albinism is a recessive trait. Determine the genotypes of the parents and offspring. a. A normal father and an albino mother have eight children, four normal (2 male & 2 female) and four albino ((2 male & 2 female) b. A normal father and an albino mother have eight children which are all normal (4 male & 4 female) c. Construct a pedigree of the families in (a) and (b). Assume that one of the normal children in (b) and one of the albino children in (a) become the parents of eight children (4 male & 4 female). Extend the pedigree to include them, predicting their phenotypes (normal or albino). ● Use "A" for the allele associated with the dominant phenotype, and lowercase "a" for the allele associated with the recessive phenotype.
2. In a species of beetles, individuals may be red, black, white or tan. Colour is controlled by a single gene with multiple alleles in a dominance series. Red (R) is dominant to black (RP), black is dominant to white (RW) and white is dominant to tan (r) (R > RD > RW > r). Colour variation in this species is a female sex-limited trait. Males carry the colour genes but are always phenotypically tan regardless of their genotype. What are the genotypes of the parents of the following cross? black female x tan males produces 151 red females: 49 black females: 61 tan females: 249 tan males
5. Flower color in snapdragons is inherited in an incompletely dominant manner. Assume that RR = red flowers, Rr = pink flowers, and rr = white flowers. What would be the genotype and phenotype ratios of the offspring of two plants with pink flowers?
3. In poultry, a gene C produces creeper (very short legs) in the heterozygous condition and is lethal in the homozygous condition. The c allele of the gene produces normal legs in the homozygous condition. Barring is due to a dominant sex-linked gene, B, and nonbarred to its recessive allele, b. In chickens, males are ZZ (similar to XX) and females are ZW (similar to XY). A creeper male homozygous for barring is mated with a creeper female who is nonbarred. What kinds of offspring can be expected from this cross and in what proportions will each kind occur?
5. In German Shepherd dogs, hair length and hip dyslpasia are determined by two different genes located on different chromosomes. In answering the following questions, use the letters D and d for fur length and H and h for hip dysplasia. Max, a long-haired dog with no hip dysplasia, was bred with Rin, a short-haired dog that was later found to have hip dysplasia. All of their children had long hair and hip dysplasia. a. Give the genotypes of the following: Мах Rin Their children (the F,) Buddy is a German Shepherd dog with short hair and was heterozygous for having hip dysplasia. b. What is Buddy's genotype? c. Give the genotypes of all of the gametes Buddy could produce.
2. In a hypothetical population of 2500 people, 2275 people have brown eyes and 225 people have blue eyes (the homozygous-recessive phenotype. If there are 4000 children produced by this generation, how many (i.e., what number) of the children would be expected to be heterozygous for eye color
5. In German cockroaches, bulging eyes (bu) are recessive to normal eyes (bu*), and curved wings (cv) are recessive to straight wings (cv*). These two traits are encoded by autosomal genes that are linked. A cockroach has genotype butbu cv*cv, and the genes are in repulsion. Which of the following sets of genes will be found in the most common gametes produced by this cockroach? a. buʻcy+ b. bu cv с. butbu d. cv*cv е. bu cvt
5. Cystic fibrosis in humans is caused by a recessive allele. Two unaffected parents have a child with cystic fibrosis. a. What is the probability that this couple's next child will be unaffected?