1. a) Draw the product for the following reaction. Note, RCO3H is a peroxy acid. 2. Draw the product for the following reaction. OH RCO3H H*, H₂O OH PCC 3. Draw the product for the following reaction. CrO 3 H₂SO4, H₂O
Reactive Intermediates
In chemistry, reactive intermediates are termed as short-lived, highly reactive atoms with high energy. They rapidly transform into stable particles during a chemical reaction. In specific cases, by means of matrix isolation and at low-temperature reactive intermediates can be isolated.
Hydride Shift
A hydride shift is a rearrangement of a hydrogen atom in a carbocation that occurs to make the molecule more stable. In organic chemistry, rearrangement of the carbocation is very easily seen. This rearrangement can be because of the movement of a carbocation to attain stability in the compound. Such structural reorganization movement is called a shift within molecules. After the shifting of carbocation over the different carbon then they form structural isomers of the previous existing molecule.
Vinylic Carbocation
A carbocation where the positive charge is on the alkene carbon is known as the vinyl carbocation or vinyl cation. The empirical formula for vinyl cation is C2H3+. In the vinyl carbocation, the positive charge is on the carbon atom with the double bond therefore it is sp hybridized. It is known to be a part of various reactions, for example, electrophilic addition of alkynes and solvolysis as well. It plays the role of a reactive intermediate in these reactions.
Cycloheptatrienyl Cation
It is an aromatic carbocation having a general formula, [C7 H7]+. It is also known as the aromatic tropylium ion. Its name is derived from the molecule tropine, which is a seven membered carbon atom ring. Cycloheptatriene or tropylidene was first synthesized from tropine.
Stability of Vinyl Carbocation
Carbocations are positively charged carbon atoms. It is also known as a carbonium ion.
\[ \chemfig{**6(------)-CH_2-CH_2} \overset{\ce{RCO3H}}{\rightarrow}
\overset{\mathrm{H^+, H2O}}{\rightarrow} \]
2. **Problem:**
Draw the product for the following reaction.
**Reaction Scheme:**
\[ \chemfig{**6(------)-CH_2-OH} \overset{\ce{PCC}}{\rightarrow}\]
3. **Problem:**
Draw the product for the following reaction.
**Reaction Scheme:**
\[ \chemfig{**6(------)-CH_2-OH} \overset{\ce{CrO3}}{\rightarrow}
\overset{\mathrm{H2SO4, H2O}}{\rightarrow}\]
### Detailed Explanation:
For each given reaction, you are required to identify the product formed when the starting material undergoes the specified chemical process.
1. **First Reaction**: The reaction involves an alkene (\texttt{**6-\chemfig{-}-} with two additional carbon atoms) treated with a peroxy acid (\texttt{\ce{RCO3H}}) in the presence of acidic water (\texttt{\ce{H^+, H2O}}). Peroxy acids typically convert alkenes into epoxides.
2. **Second Reaction**: A benzyl alcohol (\texttt{**6(------)-CH_2-OH}) is oxidized using PCC (Pyridinium chlorochromate). PCC generally converts primary alcohols into aldehydes.
3. **Third Reaction**: A benzyl alcohol (\texttt{**6(------)-CH_2-OH}) is oxidized in the presence of chromic acid (\texttt{\ce{CrO3}}), sulfuric acid (\texttt{\ce{H2SO4}}), and water (\texttt{\ce{H2O}}). This typically results](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F44572439-aee9-40a4-8ec4-b1e043de89f6%2Fd0516efa-d1f0-431d-b34f-2114ffee24f9%2Fs9bmin9_processed.jpeg&w=3840&q=75)
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