**Subpart 1: Newton's Second Law along the y-axis**(i) Write Newton's Second Law along the y-axis by adding all forces in the y-direction, taking into account their signs (forces pointing upwards are positive and downward are negative) in terms of the normal force \( N \), weight \( mg \), force \( F \), and angle \( \theta \).In both scenarios, there is no acceleration along the y-direction, therefore, \( a_y = 0 \).\[\sum F_y = -F \sin \theta + N - mg = m \cdot a_y = 0 \quad (1)\](ii) Using (1) to solve for \( N \).\[N = mg + F \sin \theta \quad (2)\]**Think:** In (2) is \( N \) greater than the weight, less than the weight, or equal to the weight?---**Subpart 2: Set up Newton's Second Law in the x-direction when the ice block is stationary.**(i) Write Newton's Second Law along the x-axis by adding all forces in the x-direction, taking into account their signs (forces pointing to the right are positive and pointing to the left are negative) when the block is not moving in terms of \( F \), \( \theta \), and the force of static friction \( f_s \).**DON'T forget the subscript on \( f_s \).**If the block is not moving, then \( a_x = 0 \).\[\sum F_x = F \cos \theta - f_s = ma_x = 0 \quad (3)\](ii) What value of static friction should you use just before the block starts moving?\( f_{s,max} = \)- \(\mu_s N \) ✅- \(\mu_k N \)---**Subpart 3: Set up Newton's Second Law in the x-direction when the ice block is accelerating to the right with an acceleration \( a \).**(i) Write Newton's Second Law along the x-axis by adding all forces in the x-direction, taking into account their signs (forces pointing to the right are positive and forces pointing to the left are negative) when the block is accelerating to the right, in terms of \( F \), \( \theta \), and the force of static friction \( f_s \) or 1. A contestant in a winter sporting event pushes a 45-kg block of ice across a frozen lake as shown in the figure. The coefficient of static friction between the block and ice is \( \mu_s = 0.1 \), and the coefficient of kinetic friction is \( \mu_k = 0.03 \). \( \theta = 25^\circ \) as shown.*Image Description:*A person is pushing a block of ice. The force applied is at an angle of 25° from the horizontal. The coordinate axes are depicted with arrows labeled X (horizontal) and Y (vertical).a) Using the equations in Subpart 1 and Subpart 2 in *Homework: Pushing a Block of Ice, Part 2*, calculate the minimum force \( F_{\text{min}} \) that must be exerted to get the block just moving.\[ F_{\text{min}} = \boxed{} \, \text{N} \]b) Using the equations in Subpart 1 and Subpart 3 in *Homework: Pushing a Block of Ice, Part 2*, what is the acceleration of the block once it starts to move if the force from part (a) is maintained, that is, \( F = F_{\text{min}} \) from part (a)?\[ a = \boxed{} \, \text{m/s}^2 \]

Name: **Subpart 1: Newton's Second Law along the y-axis**(i) Write Newton's
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Description: **Subpart 1: Newton's Second Law along the y-axis**(i) Write Newton's Second Law along the y-axis by adding all forces in the y-direction, taking into account their signs (forces pointing upwards are positive and downward are negative) in terms of t

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1. A contestant in a winter sporting event pushes a 45-kg block of ice across a frozen lake as shown in the figure. The coefficient of static friction between the block and ice is μ = 0.1, and the coefficient of kinetic friction is μ = 0.03. 0= 25° as shown. 25° y a) Using the equations in Subpart 1 and Subpart 2 in Homework: Pushing a Block of Ice, Part 2, calculate the minimum force Fmin that must be exerted to get the block just moving. Fmin = N (b) Using the equations in Subpart 1 and Subpart 3 in Homework: Pushing a Block of Ice, Part 2, What is the acceleration of the block once it starts to move if the force from part (a) is maintained, that is, F= Fmin from part (a)?

1. A contestant in a winter sporting event pushes a 45-kg block of ice across a frozen lake as shown in the figure. The coefficient of static friction between the block and ice is μ = 0.1, and the coefficient of kinetic friction is μ = 0.03. 0= 25° as shown. 25° y a) Using the equations in Subpart 1 and Subpart 2 in Homework: Pushing a Block of Ice, Part 2, calculate the minimum force Fmin that must be exerted to get the block just moving. Fmin = N (b) Using the equations in Subpart 1 and Subpart 3 in Homework: Pushing a Block of Ice, Part 2, What is the acceleration of the block once it starts to move if the force from part (a) is maintained, that is, F= Fmin from part (a)?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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