1. A conical pendulum is formed by attaching a mass m to a string of length L, then allowing the mass to swing in a horizontal circle. The string makes a constant angle 0 with respect to the vertical; as a result, the mass moves with a constant speed in a horizontal circle. (a) Find an expression for the magnitude of the tension in the string. Put your answers in terms of m, L, 0, and/or g. (b) Find the speed v of the mass in terms of m, L, 0, and/or g. (c) If the mass is 500 g, the length of the string is 1.00 m, and the angle is 11.5°, then what is the tension in the string and the speed of the mass? L Point of support 3

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1. A conical pendulum is formed by attaching a mass m to a string of
length L, then allowing the mass to swing in a horizontal circle. The
string makes a constant angle with respect to the vertical; as a
result, the mass moves with a constant speed in a horizontal circle.
(a) Find an expression for the magnitude of the tension in the
string. Put your answers in terms of m, L, 0, and/or g.
(b) Find the speed v of the mass in terms of m, L, 0, and/or g.
(c) If the mass is 500 g, the length of the string is 1.00 m, and the
angle is 11.5°, then what is the tension in the string and the
speed of the mass?
L
Ꮎ
Point of
support
Copyright ©296 Pon Education publishing Pearson Addo
m
Transcribed Image Text:1. A conical pendulum is formed by attaching a mass m to a string of length L, then allowing the mass to swing in a horizontal circle. The string makes a constant angle with respect to the vertical; as a result, the mass moves with a constant speed in a horizontal circle. (a) Find an expression for the magnitude of the tension in the string. Put your answers in terms of m, L, 0, and/or g. (b) Find the speed v of the mass in terms of m, L, 0, and/or g. (c) If the mass is 500 g, the length of the string is 1.00 m, and the angle is 11.5°, then what is the tension in the string and the speed of the mass? L Ꮎ Point of support Copyright ©296 Pon Education publishing Pearson Addo m
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