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1. A city of 150,000 people discharges sewage, after removing 90% of the total suspended solids (TSS), into a stream with 0 TSS and a flow of 50 m3/min. A newspaper critic stated that what the city is doing is equivalent to discharging untreated sewage from 15,000 people. Is this criticism fair? Assume that each person produces 2.67 x 104 m/min of wastewater with a TSS concentration of 200 mg/L.

1. A city of 150,000 people discharges sewage, after removing 90% of the total suspended solids (TSS), into a stream with 0 TSS and a flow of 50 m3/min. A newspaper critic stated that what the city is doing is equivalent to discharging untreated sewage from 15,000 people. Is this criticism fair? Assume that each person produces 2.67 x 104 m/min of wastewater with a TSS concentration of 200 mg/L.

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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For some reason this question keeps getting rejected for b.s. reasons. Please do not reject the question even if I you aren't confident in your answer just poSt it any way
Snow Loads : ASCE 7- 16 Nominal Snow Forces Roof slope Horiz. eave to ridge dist (W) = Roof length parallel to ridge (L) = 18.4 deg 18.0 ft 72.0 ft Type of Roof Ground Snow Load Hip and gable w/ rafters Pg = 46.0 psf Risk Category Importance Factor Thermal Factor II 1.0 Ct = 1.10 Exposure Factor Ce = 1.2 Pf = 0.7*Ce*Ct*I'Pg Unobstructed Slippery Surface 42.5 psf %3D yes Sloped-roof Factor Balanced Snow Load Cs = 0.86 36.5 psf Near ground level surface balanced snow load = 46.0 psf Rain on Snow Surcharge Angle Code Maximum Rain Surcharge Rain on Snow Surcharge Ps plus rain surcharge Minimum Snow Load 0.36 deg 5.0 psf 0.0 psf 36.5 psf 0.0 psf %3D Pm = NOTE: Alternate spans of continuous beams shall be loaded with half the design roof snow load so as to produce the greatest possible effect - see code for loading diagrams and exceptions for gable roofs.. Uniform Roof Design Snow Load = 36.5 psf Unbalanced Snow Loads - for Hip & Gable roofs only 30.26 deg Required if slope is between 7 on 12 = and 2.38 deg = 2.38 deg Unbalanced snow loads must be applied Windward snow load = Leeward snow load = 0.0 psf 46.0 psf = 1* Pg Windward Snow Drifts 1 - Against walls, parapets, etc Upwind fetch Projection height Snow density Balanced snow height lu = 15.0 ft h = 3.0 ft 20.0 pcf hb = 1.83 ft hd = hc = 1.27 ft 1.17 ft Therefore, design for drift 1.17 ft 5.50 ft 23.4 psf 36.5 psf Surcharge Load Due to Drifting hc/hb >0.2 = 0.6 Drift height (hc) Drift width Surcharge load: hc W = pd = y*hd = hd pd Balanced Snow Load Balanced Snow load: hb 59.9 psf Windward Snow Drifts 2 - Against walls, parapets, etc 24.0 ft Lu Upwind fetch Projection height Snow density Balanced snow height lu = h = 4.0 ft 20.0 pct 1.83 ft %3D hb = Note: If bottom of projection is at least 2 feet above hb then snow drift is not required. 1.42 ft 2.17 ft Therefore, design for drift 1.42 ft 5.68 ft 28.4 psf 36.5 psf 64.9 psf hd = hc = hc/hb >0.2 = 1.2 Drift height (hd) Drift width Surcharge load: W = pd = y*hd = Balanced Snow load:
Transcribed Image Text:Snow Loads : ASCE 7- 16 Nominal Snow Forces Roof slope Horiz. eave to ridge dist (W) = Roof length parallel to ridge (L) = 18.4 deg 18.0 ft 72.0 ft Type of Roof Ground Snow Load Hip and gable w/ rafters Pg = 46.0 psf Risk Category Importance Factor Thermal Factor II 1.0 Ct = 1.10 Exposure Factor Ce = 1.2 Pf = 0.7*Ce*Ct*I'Pg Unobstructed Slippery Surface 42.5 psf %3D yes Sloped-roof Factor Balanced Snow Load Cs = 0.86 36.5 psf Near ground level surface balanced snow load = 46.0 psf Rain on Snow Surcharge Angle Code Maximum Rain Surcharge Rain on Snow Surcharge Ps plus rain surcharge Minimum Snow Load 0.36 deg 5.0 psf 0.0 psf 36.5 psf 0.0 psf %3D Pm = NOTE: Alternate spans of continuous beams shall be loaded with half the design roof snow load so as to produce the greatest possible effect - see code for loading diagrams and exceptions for gable roofs.. Uniform Roof Design Snow Load = 36.5 psf Unbalanced Snow Loads - for Hip & Gable roofs only 30.26 deg Required if slope is between 7 on 12 = and 2.38 deg = 2.38 deg Unbalanced snow loads must be applied Windward snow load = Leeward snow load = 0.0 psf 46.0 psf = 1* Pg Windward Snow Drifts 1 - Against walls, parapets, etc Upwind fetch Projection height Snow density Balanced snow height lu = 15.0 ft h = 3.0 ft 20.0 pcf hb = 1.83 ft hd = hc = 1.27 ft 1.17 ft Therefore, design for drift 1.17 ft 5.50 ft 23.4 psf 36.5 psf Surcharge Load Due to Drifting hc/hb >0.2 = 0.6 Drift height (hc) Drift width Surcharge load: hc W = pd = y*hd = hd pd Balanced Snow Load Balanced Snow load: hb 59.9 psf Windward Snow Drifts 2 - Against walls, parapets, etc 24.0 ft Lu Upwind fetch Projection height Snow density Balanced snow height lu = h = 4.0 ft 20.0 pct 1.83 ft %3D hb = Note: If bottom of projection is at least 2 feet above hb then snow drift is not required. 1.42 ft 2.17 ft Therefore, design for drift 1.42 ft 5.68 ft 28.4 psf 36.5 psf 64.9 psf hd = hc = hc/hb >0.2 = 1.2 Drift height (hd) Drift width Surcharge load: W = pd = y*hd = Balanced Snow load:
4. A city of 150,000 people discharges sewage, after removing 90% of the total suspended solids (TSS), into a stream with 0 TSS and a flow of 50 m³/min. A newspaper critic stated that what the city is doing is equivalent to discharging untreated sewage from 15,000 people. Is this criticism fair? Assume that each person produces 2.67 x 104 m3/min of wastewater with a TSS concentration of 200 mg/L.
Transcribed Image Text:4. A city of 150,000 people discharges sewage, after removing 90% of the total suspended solids (TSS), into a stream with 0 TSS and a flow of 50 m³/min. A newspaper critic stated that what the city is doing is equivalent to discharging untreated sewage from 15,000 people. Is this criticism fair? Assume that each person produces 2.67 x 104 m3/min of wastewater with a TSS concentration of 200 mg/L.
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