1. A charge Q is uniformly distributed over a large plastic plate. The electric field at a point P close to the centre of the plate is 10 V m. If the plastic plate is replaced by a copper plate of the same geometrical dimensions and carrying the same charge Q, the electric field at the point P will become (a) zero (b) 5 V m (c) 10 V m (d) 20 V m.
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- A small plastic ball with a mass of 6.5 x 10-3 kg and with a charge of +0.15 uC is suspended from insulating thread and hangs between the plates of capacitor. The ball is in equilibrium with the thread making an angle of 30 degrees with respect to vertical. The ball is displaced by 0.15 m from its vertical position. What is the magnitude of the electric field between the two plates?21.84 . CALC A semicircle of radius a is in the first and second y. quadrants, with the center of cur- vature at the origin. Positive charge +Q is distributed uniformly around the left half of the semicircle, and negative charge -Q is distributed uniformly around the right half of the semicircle (Fig. P21.84). What are the magnitude and direction of the net electric field at the origin produced by this distribution of charge? +Q x-24.
- Electric fields exert a force on a charged particle, which makes it want to move. True/false Insulators are a category of material in which charges may freely move. True/FalseThe membrane surrounding a living cell consists of an inner and an outer wall that are separated by a small space. Assume that the membrane acts like a parallel plate capacitor in which the effective charge density on the inner and outer walls has a magnitude of 6.8 × 10-6 C/m2. (a) What is the magnitude of the electric field within the cell membrane? (b) Find the magnitude of the electric force that would be exerted on a potassium ion (K+; charge = +e) placed inside the membrane.parallel-plate capacitors are widely used in electronics such as preventing direct current leakage. An electric field is generated between a pair of plates that has a surface charge density of 7.70 x 10^-6 C/m^2 The plates are seperated by 0.49 um. a) what is the magnitude of the electric field between the plates ? b) suppose the thickness of the plates doubled, would my answer increase, decrease, or remain the same?
- An electron is placed at rest in an electric field of 510 N/C. Which of the followings is the speed of the electron 47.0 ns after being released?Problem 12: A simple and common technique for accelerating electrons is shown in the figure, which depicts a uniform electric field between two plates. Electrons are released, usually from a hot filament, near the negative plate, and there is a small hole in the positive plate that allows the electrons to pass through. E = 2.4 × 104 N/C Calculate the horizontal component of the electron's acceleration if the field strength is 2.4 × 104 N/C. Express your answer in meters per second squared, and assume the electric field is pointing in the negative x-direction as shown in the figure.A small object of mass 3.54 g and charge −19.3 ?C is suspended motionless above the ground when immersed in a uniform electric field perpendicular to the ground. What are the magnitude and direction of the electric field? magnitude direction
- An electron is projected into a uniform electric field that has a magnitude of 500 N/C. The direction of the electric field is vertically upward. The initial velocity of the electron has a magnitude of 6.00x10^6 m/s, and its direction is at an angle of 30°above the horizontal. Find:I. The maximum distance the electron rises vertically above its initial elevation.II. After what horizontal distance does the electron return to its original elevation.I need help for these questions, I am studying for the physics exam and I couldn't solve this questions which are in the study plan of physics-102. Thanks in advance.