1. A Carnot cycle has a maximum temperature of 550 °F and minimum temperature of 100 °F. If the horsepower output of the engine is 44.13, find the heat added for the cycle in BTU/s. Use these values when necessary:Specific Heat Ratio (k)O2 - 1.395Co2 = 1.288Cpwater = 4.187 kJ/kgH2 - 1.4He = 1.667NH3 = 1.304N2 = 1.399Hg = 1.666CH: = 1.321K; Cpair = 1 kJ/kg- K; Cpatean = 2 kJ/kg - K1 kg - 2.205 lb"C to K = (use + 273.15)1 bar = 100 kPa1 BTU = 1.055 kJ = 778 ft - lb1 HP = 0. 746 kW = 2545 BTU/hr= 6.5748 kJ/kg - K@ 1.03425 MPa:@ 2.5 MPa :@ 7MPA and 550 deg C:= 2779. 4 kJ/kg; Sghg = 2803.1 kJ/kg; Sg = 6.2575 kJ/ kgh: = 3530.9 kJ/kg; s: = 6.9486 kJ/kg- K- K

Given data, Tmax = 550°F = 560.928 K Tmin = 100°F = 310.928 K P(output) = 44.13 hp Find Q(added) =…

Answered: 1. A Carnot cycle has a maximum…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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1. A Carnot cycle has a maximum temperature of 550 °F and minimum temperature of 100 °F. If the horsepower output of the engine is 44.13, find the heat added for the cycle in BTU/s.

Use these values when necessary:
Specific Heat Ratio (k)
O2 - 1.395
Co2 = 1.288
Cpwater = 4.187 kJ/kg
H2 - 1.4
He = 1.667
NH3 = 1.304
N2 = 1.399
Hg = 1.666
CH: = 1.321
K; Cpair = 1 kJ/kg
- K; Cpatean = 2 kJ/kg - K
1 kg - 2.205 lb
"C to K = (use + 273.15)
1 bar = 100 kPa
1 BTU = 1.055 kJ = 778 ft - lb
1 HP = 0. 746 kW = 2545 BTU/hr
= 6.5748 kJ/kg - K
@ 1.03425 MPa:
@ 2.5 MPa :
@ 7MPA and 550 deg C:
= 2779. 4 kJ/kg; Sg
hg = 2803.1 kJ/kg; Sg = 6.2575 kJ/ kg
h: = 3530.9 kJ/kg; s: = 6.9486 kJ/kg
- K
- K

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