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1. A capacitor is composed of 2 plates separated by a sheet of insulating material 2mm thick and of relative permittivity 3. The distance between the plates is increased to allow the insertion of a second sheet of 3mm thick and of relative permittivity &r . If the equivalent capacitance is one-half of the original capacitance, find the value of ɛr. Ans: ɛ, = 4. 5 G C2 2. In the given network, each capacitor has C = 4.00 µF and Vab = +28. 0 V. Calculate the: C3 a. Total capacitance Ans: CT = 2.4µF b. Charge on each capacitor Ans: Q1 = Q2 c. Potential difference on each capacitor Ans: V1 = V2 = 5. 6V, V3 = 11.2V, V4 = 16. 8V 22.4µC, Q3 = 44. 8µC, Q4 = 67.2µC %3D 3. A 20 µF capacitor is charged to 120 V and then disconnected from the power supply. If a second uncharged capacitor with capacitance of 50 µF is connected across the first capacitor, what would be the resulting voltage across their parallel combination? Ans: Vr 4. A parallel-plate capacitor in air has a plate separation of 1.35 cm and a plate area of 35.0 cm². The plates are charged to a potential difference of 150 V and disconnected from the source. The capacitor is then immersed in distilled water. Assume the liquid is an insulator. Determine: a. the charge on the plates before and after immersion Ans: Q = 344. 33 pC b. the capacitance and potential difference after immersion Ans: C = 183. 65PF, V = 1.875V c. the change in energy of the capacitor after immersion Ans: AU = –25. 5nJ = 34. 286V 5. Find the relative permittivity ɛr of the dielectric material present in a parallel-plate capacitor if: A = 0.12 m², d = 80 µm, V =12 V, U =1 µJ Ans: ɛ, = 1.046

1. A capacitor is composed of 2 plates separated by a sheet of insulating material 2mm thick and of relative permittivity 3. The distance between the plates is increased to allow the insertion of a second sheet of 3mm thick and of relative permittivity &r . If the equivalent capacitance is one-half of the original capacitance, find the value of ɛr. Ans: ɛ, = 4. 5 G C2 2. In the given network, each capacitor has C = 4.00 µF and Vab = +28. 0 V. Calculate the: C3 a. Total capacitance Ans: CT = 2.4µF b. Charge on each capacitor Ans: Q1 = Q2 c. Potential difference on each capacitor Ans: V1 = V2 = 5. 6V, V3 = 11.2V, V4 = 16. 8V 22.4µC, Q3 = 44. 8µC, Q4 = 67.2µC %3D 3. A 20 µF capacitor is charged to 120 V and then disconnected from the power supply. If a second uncharged capacitor with capacitance of 50 µF is connected across the first capacitor, what would be the resulting voltage across their parallel combination? Ans: Vr 4. A parallel-plate capacitor in air has a plate separation of 1.35 cm and a plate area of 35.0 cm². The plates are charged to a potential difference of 150 V and disconnected from the source. The capacitor is then immersed in distilled water. Assume the liquid is an insulator. Determine: a. the charge on the plates before and after immersion Ans: Q = 344. 33 pC b. the capacitance and potential difference after immersion Ans: C = 183. 65PF, V = 1.875V c. the change in energy of the capacitor after immersion Ans: AU = –25. 5nJ = 34. 286V 5. Find the relative permittivity ɛr of the dielectric material present in a parallel-plate capacitor if: A = 0.12 m², d = 80 µm, V =12 V, U =1 µJ Ans: ɛ, = 1.046

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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
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1. A capacitor is composed of 2 plates separated by a sheet of insulating material 2mm thick and of relative permittivity 3. The distance between the plates is increased to allow the insertion of a second sheet of 3mm thick and of relative permittivity ɛr. If the equivalent capacitance is one-half of the original capacitance, find the value of ɛr. Ans: ɛ, = 4. 5 C C2 2. In the given network, each capacitor has C = 4.00 µF and V ab +28. 0 V. Calculate the: C3 a. Total capacitance Ans: CT b. Charge on each capacitor Ans: Q1 = Q2 c. Potential difference on each capacitor Ans: V1 = V2 = 5. 6V, V3 = 11.2V, V4 = 2.4µF =22.4μC, Q44.8μC, Q67. 2 μC = 16. 8V %3D C4 3. A 20 µF capacitor is charged to 120 V and then disconnected from the power supply. If a second uncharged capacitor with capacitance of 50 µF is connected across the first capacitor, what would be the resulting voltage across their parallel combination? Ans: VT 4. A parallel-plate capacitor in air has a plate separation of 1.35 cm and a plate area of 35.0 cm2. The plates are charged to a potential difference of 150 V and disconnected from the source. The capacitor is then immersed in distilled water. Assume the liquid is an insulator. Determine: a. the charge on the plates before and after immersion Ans: Q = 344. 33 pC b. the capacitance and potential difference after immersion Ans: C = 183. 65PF, V = 1.875V c. the change in energy of the capacitor after immersion Ans: AU = -25. 5nJ 34. 286V %3D 5. Find the relative permittivity ɛr of the dielectric material present in a parallel-plate capacitor if: A = 0.12 m2, d = 80 µm, V =12 V, U =1 µJ Ans: Ɛr = 1.046
Transcribed Image Text:1. A capacitor is composed of 2 plates separated by a sheet of insulating material 2mm thick and of relative permittivity 3. The distance between the plates is increased to allow the insertion of a second sheet of 3mm thick and of relative permittivity ɛr. If the equivalent capacitance is one-half of the original capacitance, find the value of ɛr. Ans: ɛ, = 4. 5 C C2 2. In the given network, each capacitor has C = 4.00 µF and V ab +28. 0 V. Calculate the: C3 a. Total capacitance Ans: CT b. Charge on each capacitor Ans: Q1 = Q2 c. Potential difference on each capacitor Ans: V1 = V2 = 5. 6V, V3 = 11.2V, V4 = 2.4µF =22.4μC, Q44.8μC, Q67. 2 μC = 16. 8V %3D C4 3. A 20 µF capacitor is charged to 120 V and then disconnected from the power supply. If a second uncharged capacitor with capacitance of 50 µF is connected across the first capacitor, what would be the resulting voltage across their parallel combination? Ans: VT 4. A parallel-plate capacitor in air has a plate separation of 1.35 cm and a plate area of 35.0 cm2. The plates are charged to a potential difference of 150 V and disconnected from the source. The capacitor is then immersed in distilled water. Assume the liquid is an insulator. Determine: a. the charge on the plates before and after immersion Ans: Q = 344. 33 pC b. the capacitance and potential difference after immersion Ans: C = 183. 65PF, V = 1.875V c. the change in energy of the capacitor after immersion Ans: AU = -25. 5nJ 34. 286V %3D 5. Find the relative permittivity ɛr of the dielectric material present in a parallel-plate capacitor if: A = 0.12 m2, d = 80 µm, V =12 V, U =1 µJ Ans: Ɛr = 1.046
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