1. A C procedure that swaps two locations in memory is shown below: void swap (int v[ ], int k) ( } int temp; temp v[k]; v[k] = v[k+1]; temp; v [k+1] MIPS code for this procedure (leaf) is given by: swap: sll $t1, $al, 2 # $t1 = k * 4 add $t1, $a0, $t1 # $t1 = v+(k*4) # (address of v[k]) # $t0 (temp) = v[k] # $t2 = w $t0, 0($t1) lw $t2, 4($t1) sw $t2, 0($t1) sw $t0, 4($t1) jr $ra v[k+1] # v[k] $t2 (v[k+1]) # v[k+1] = $t0 (temp) # return to calling routine a) Use QtSpim MIPS simulator to run the code for v [ k] =20 and v [k+1] =10 b) Report a print screen of the code and result.
1. A C procedure that swaps two locations in memory is shown below: void swap (int v[ ], int k) ( } int temp; temp v[k]; v[k] = v[k+1]; temp; v [k+1] MIPS code for this procedure (leaf) is given by: swap: sll $t1, $al, 2 # $t1 = k * 4 add $t1, $a0, $t1 # $t1 = v+(k*4) # (address of v[k]) # $t0 (temp) = v[k] # $t2 = w $t0, 0($t1) lw $t2, 4($t1) sw $t2, 0($t1) sw $t0, 4($t1) jr $ra v[k+1] # v[k] $t2 (v[k+1]) # v[k+1] = $t0 (temp) # return to calling routine a) Use QtSpim MIPS simulator to run the code for v [ k] =20 and v [k+1] =10 b) Report a print screen of the code and result.
C++ Programming: From Problem Analysis to Program Design
8th Edition
ISBN:9781337102087
Author:D. S. Malik
Publisher:D. S. Malik
Chapter15: Recursion
Section: Chapter Questions
Problem 8SA
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Please send me answer within 10 min!Q! I will rate you good for sure!! Please answer all the questions with explanation with screen shot if needed.
![1. A C procedure that swaps two locations in memory is shown below:
void swap (int v[ ], int k)
{
}
int temp;
temp v[k];
v[k] = v[k+1];
v [k+1]
temp;
=
=
MIPS code for this procedure (leaf) is given by:
swap: s11 $t1, $al, 2 # $t1 = k * 4
add $t1, $a0, $t1 # $t1 = v+(k*4)
lw $t0, 0($t1)
lw $t2, 4($t1)
sw $t2, 0($t1)
sw $t0, 4($t1)
jr $ra
# (address of v[k])
# $t0 (temp) = v[k]
# $t2 = v[k+1]
# v[k] =
$t2 (v[k+1])
$t0 (temp)
# v[k+1]
# return to calling routine
a) Use QtSpim MIPS simulator to run the code for v [k] =20 and v[k+1] =10
b) Report a print screen of the code and result.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd40f66d4-4ddc-40f3-a91f-ed9afa5d78d5%2F259f0ae4-7358-4049-8124-0c2c36372bad%2Fwu3r9k9_processed.png&w=3840&q=75)
Transcribed Image Text:1. A C procedure that swaps two locations in memory is shown below:
void swap (int v[ ], int k)
{
}
int temp;
temp v[k];
v[k] = v[k+1];
v [k+1]
temp;
=
=
MIPS code for this procedure (leaf) is given by:
swap: s11 $t1, $al, 2 # $t1 = k * 4
add $t1, $a0, $t1 # $t1 = v+(k*4)
lw $t0, 0($t1)
lw $t2, 4($t1)
sw $t2, 0($t1)
sw $t0, 4($t1)
jr $ra
# (address of v[k])
# $t0 (temp) = v[k]
# $t2 = v[k+1]
# v[k] =
$t2 (v[k+1])
$t0 (temp)
# v[k+1]
# return to calling routine
a) Use QtSpim MIPS simulator to run the code for v [k] =20 and v[k+1] =10
b) Report a print screen of the code and result.
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