1. A buffer is prepared containing 1.00 molar Acetic Acid and 1.00 molar Sodium Acetate. What is its pH if the Ka of acetic acid is 1.77 x 10 -5

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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USEFUL FORMULA
pKa = - log Ka
pH = pKa + log A- / HA
pH = pKa + log A-/ HA
pH = pKa + log (equivalent salt-
%3D
%3D
equivalent acid added).
(equivalent acid +
equivalent acid added)
Buffer capacity = no. of
%3D
equivalent acid/base added
4 in pH x vouтe
in liters
Part II
1. A buffer is prepared containing 1.00 molar Acetic
Acid and 1.00 molar Sodium Acetate. What is its pH
if the Ka of acetic acid is 1.77 x 10 -5
2. Calculate the pH using Henderson-Hasselbalch
equation of a 50mL buffer solution made from 0.20
M HC2H302 and 0.50 M C2H3O2- that has an acid
dissociation constant, Ka for HC2H302 of 1.8 x 10
a.) What will be the change in pH of the
buffer solution after the addition of 1.0 mL of 0.10N
HCI
b.) What is the total buffer capacity of the
solution?
Transcribed Image Text:USEFUL FORMULA pKa = - log Ka pH = pKa + log A- / HA pH = pKa + log A-/ HA pH = pKa + log (equivalent salt- %3D %3D equivalent acid added). (equivalent acid + equivalent acid added) Buffer capacity = no. of %3D equivalent acid/base added 4 in pH x vouтe in liters Part II 1. A buffer is prepared containing 1.00 molar Acetic Acid and 1.00 molar Sodium Acetate. What is its pH if the Ka of acetic acid is 1.77 x 10 -5 2. Calculate the pH using Henderson-Hasselbalch equation of a 50mL buffer solution made from 0.20 M HC2H302 and 0.50 M C2H3O2- that has an acid dissociation constant, Ka for HC2H302 of 1.8 x 10 a.) What will be the change in pH of the buffer solution after the addition of 1.0 mL of 0.10N HCI b.) What is the total buffer capacity of the solution?
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