1. A bismuth isotope decays into thallium by emitting an alpha particle according to the following equation: All particles mass # 217 Bi atomic #83 → TI + He only protons (a) Determine the atomic number Z and the mass number A of the thallium nuclei produced and enter your answers in the spaces provided below. Z = 81 1 = 213 The mass of the alpha particle is 6.64 x 10-27 kg. Its measured kinetic energy is 6.09 MeV and its speed is muc less than the speed of light. 26.09 ebev (a) Determine the momentum of the alpha particle. (1.14 x 10-¹9 kg m/s) K=1/mv² 9.744e-13= 1/2 ( P=my (6.64x10-27) ² 0.00P dige v=1.713e7 m/s. Holl ini su li Physics (b) Determine the kinetic energy of the recoiling thallium nucleus. (1.93 x 10-¹4 J) P- 6.64 x 10-27 (1.713e7) 1.138e-19 kgm/s) P 9,744 provetopis (c) Determine the total energy released during the decay of 1 mole of bismuth 212: (5.98 x 10¹¹J) ora
1. A bismuth isotope decays into thallium by emitting an alpha particle according to the following equation: All particles mass # 217 Bi atomic #83 → TI + He only protons (a) Determine the atomic number Z and the mass number A of the thallium nuclei produced and enter your answers in the spaces provided below. Z = 81 1 = 213 The mass of the alpha particle is 6.64 x 10-27 kg. Its measured kinetic energy is 6.09 MeV and its speed is muc less than the speed of light. 26.09 ebev (a) Determine the momentum of the alpha particle. (1.14 x 10-¹9 kg m/s) K=1/mv² 9.744e-13= 1/2 ( P=my (6.64x10-27) ² 0.00P dige v=1.713e7 m/s. Holl ini su li Physics (b) Determine the kinetic energy of the recoiling thallium nucleus. (1.93 x 10-¹4 J) P- 6.64 x 10-27 (1.713e7) 1.138e-19 kgm/s) P 9,744 provetopis (c) Determine the total energy released during the decay of 1 mole of bismuth 212: (5.98 x 10¹¹J) ora
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how would you do part b of this question? this is a non graded practice worksheet
![1. A bismuth isotope decays into thallium by emitting an alpha particle according
to the following equation:
→217
mass #
All particles
atomic #83
Bi
He
only
protons
(a) Determine the atomic number Z and the mass number A of the thallium nuclei produced and enter your
answers in the spaces provided below.
Z == 81
1 = 213
The mass of the alpha particle is 6.64 x 10-27 kg. Its measured kinetic energy is 6.09 MeV and its speed is much
less than the speed of light.
26.09 ebev
(a) Determine the momentum of the alpha particle. (1.14 x 10-¹9 kg m/s)
K=//mv²
9.744e-13=116.64x10-27) ²
P=my
→ TI +
0.00P dige
v=1.713e7 m/s
Plyysics
(b) Determine the kinetic energy of the recoiling thallium nucleus. (1.93 x 10-14 J)
P - 6,64 x 10-27 (1. 713e7)
P
1.138e-19 kgm/s)
9.744e-13 J
pretopte
(c) Determine the total energy released during the decay of 1 mole of bismuth 212: (5.98 x 10¹¹J)
ora](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6dac1fe8-9484-432e-9121-04aedd30c8dd%2F0566dd76-4c26-4f97-92a5-cb4d244bb399%2Fbpqphxf_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1. A bismuth isotope decays into thallium by emitting an alpha particle according
to the following equation:
→217
mass #
All particles
atomic #83
Bi
He
only
protons
(a) Determine the atomic number Z and the mass number A of the thallium nuclei produced and enter your
answers in the spaces provided below.
Z == 81
1 = 213
The mass of the alpha particle is 6.64 x 10-27 kg. Its measured kinetic energy is 6.09 MeV and its speed is much
less than the speed of light.
26.09 ebev
(a) Determine the momentum of the alpha particle. (1.14 x 10-¹9 kg m/s)
K=//mv²
9.744e-13=116.64x10-27) ²
P=my
→ TI +
0.00P dige
v=1.713e7 m/s
Plyysics
(b) Determine the kinetic energy of the recoiling thallium nucleus. (1.93 x 10-14 J)
P - 6,64 x 10-27 (1. 713e7)
P
1.138e-19 kgm/s)
9.744e-13 J
pretopte
(c) Determine the total energy released during the decay of 1 mole of bismuth 212: (5.98 x 10¹¹J)
ora
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