1. A bell-shaped distribution has a mean µ 1. Find the proportion of data between 1200 and 1540. 2. Find the proportion of data above 1540. 2. A data set with an unknown distribution has mean µ = 360 and standard deviation o = 1200 and standard deviation o = 340. :20. 1. State Chebyshev Theorem. 2. Provide a lower estimate of the proportion of data between 315 and 405.

1. A bell-shaped distribution has a mean µ 1. Find the proportion of data between 1200 and 1540. 2. Find the proportion of data above 1540. 2. A data set with an unknown distribution has mean µ = 360 and standard deviation o = 1200 and standard deviation o = 340. :20. 1. State Chebyshev Theorem. 2. Provide a lower estimate of the proportion of data between 315 and 405.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

6. Section 5.7 Number 46 parts b and c only 46. According to the College Board, scores on the Math SAT for the class of 2017 had a mean of 527 and a standard deviation of 107. Assume that they are roughly normally distributed. a. What was the interval spanned by the middle 50% of scores? b. What was the interval spanned by the middle 68% of scores? c. How high must a student score in order to be in the top 2.5% of scores?
1. Find the percentage of N.d. observations with a zz-score between z1= -3.04 and z2 = 2.85. Give your answer to two decimal places. 2. Find the proportion of N.d. observations with a zz-score between z1= -2.95 and z2 = 0.70. Give your answer to four decimal places.
8. a) The mean of 6 different plots of acidic soil samples is 3.2. An extra plot with pH value 3.9 is included in the sample. What is the new mean? b) Five soil samples have a mean of 12 dS/m for soil electrical conductivity (EC). When a soil sample was removed, the mean is 11 dS/m. What is the value of the soil EC been removed? 9. Loss of calcium is a serious problem for older women. At the beginning of a study on the influence of exercise on the rate of loss, the amounts of bone mineral content in the radius bone of the dominant hand of 11 elderly women were: 0.88, 1.06, 0.90, 1.06, 0.79, 0.80, 0.85, 0.91, 0.94, 1.00, 0.72 Calculate: (a) The mean. (b) The median. (c) The mode. (d) A researcher says: "The mode seems to be the best average to represent the data in this survey." Give ONE reason to support this statement.
8. A list of exam scores shows that the raw score of X = 50 corresponds to z = -2.00 and a raw score of X = 62 corresponds to z = +1.00. Find the mean and standard deviation for the distribution of raw scores.
6. A distribution with a µ = 55 and o = 6 is standardized so that the new mean and standard deviation will be u = 50 and o = 10. When the new distribution is standardized, what value will be obtained for a score of x = 52 from the original distribution? a. X= 45 b. X = 47 C. X= 52 d. X = 53
I hope the solution is to choose the correct one only, no more
5. Bone mineral density (BMD) is a measure of bone strength. It is defined as the ratio of bone mass to the cross- sectional area of the bone that is scanned, and it is expressed in units of grams per square centimeter (g/cm²). Recent studies suggest that peak BMD in women is achieved between ages 15 and 40, and BMD declines after age 45. Decreased BMD is associated with increased risk of bone fracture. In a recent study, the impact of regular physical exercise on women in differing stages of BMD development was examined. A simple random sample of 59 women between the ages of 41 and 45 and with no major health problems were enrolled in the study. The women were classified into one of the two following groups, based on their level of exercise activity. • Sedentary: minimal participation in physical exercise in the past three years (This group contained 31 women.) • Walkers: walk at an aerobic pace at least 135 minutes per week during the past three years (This group contained 28 women.)…
4.3 Suppose the heights of all female students at University of Maryland in College Park are known to be normally distributed with u 5'5" and o= 2'', find the percentage of female students = a. under 5'2". b. between 5'2" and 5'8". c. between 5'8" and 5'9".
43. From the following data compute the value of harmonic mean: 20-30 30-40 40-50 10-20 50-60 Class interval 6 S 10 7. Frequency
5. Find P( 480 < X-bar < 520) · Given : The average test score (u) in 2020 of a Standardized Accounting Exam was 550 with a population standard deviation (0) of 45. 6. . Find Lowest Test Score x which is in the 95 Percentile. 7. Find Lowest Test Score x which is in the 75st Percentile. 8. Find Lowest Test Score x which is in the 25 Percentile. Given that an Independent Education Research team desires to estimate the population GPA, µ, of Gulf Coast State College for the year 2020. The sample mean was 3.15. Ass population standard deviation of 0.85 (0). 9. A sample of n= 100 students was selected at random. Find the 95% Confidence Interval for u and interpret your results. Given that an Independent Education Research team desires to estimate the popula GPA, µ, of Pensacola State College for the year 2020. The sample mean was 3.11. 0.7 Tunnora a i not giuen and n= 29 students were selected at random. Assume s =
4.Calculation (1020'=20') Study the relationship between monthly household consumption expenditure y and monthly household disposable X in the community. Set the measurement model as: Y=B1+B₂X+μ Sample data Xi, Yi, Xiyi Xiyi, xi², and sample mean value are shown in the following table. 2 Xi Yi Xi Yi Xiyi Xi 1 800 638 -1350 -945 1275750 1822500 2 1100 935 -1050 -648 680400 1102500 3 1400 1155 -750 -428 321000 562500 4 1700 1254 -450 -329 148050 202500 5 2000 1408 -150 -175 26250 22500 6 2300 1650 150 67 10050 22500 7 2600 1925 450 342 153900 202500 8 2900 2068 750 485 363750 562500 9 3200 2267 1050 684 718200 1102500 10 3500 2530 1350 947 1278450 1822500 Sum 21500 15830 1 49758000 74250000 Mean 2150 1583 1 1 1 1