1. (a) (b) (c) (d) Find Maclaurin series for the function e-2x 2² 2³ 1+2x-x + _ 2! 22 2x+x 3! 1-2x² + 2 2² - - 1-2x +- 2³ P 4! 2! 2² =x². 2! 3! - et. x +... 2³ 3! 2³ 2 3! +... x+.. x²³+...

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Problem 1: Maclaurin Series for the Function**

Find the Maclaurin series for the function \( e^{-2x} \).

**Options:**

(a) \( 1 + 2x - \frac{2^2}{2!}x^2 + \frac{2^3}{3!}x^3 + \cdots \)

(b) \( 2x + \frac{2^2}{3!}x^2 - \frac{2^3}{4!}x^3 + \cdots \)

(c) \( 1 - 2x + \frac{2^2}{2!}x^2 - \frac{2^3}{3!}x^3 + \cdots \)

(d) \( 1 - 2x + \frac{2^2}{2!}x^2 - \frac{2^3}{3!}x^3 + \cdots \)

**Explanation:**

The task is to determine which of the given options correctly represents the Maclaurin series expansion for the function \( e^{-2x} \).
Transcribed Image Text:**Problem 1: Maclaurin Series for the Function** Find the Maclaurin series for the function \( e^{-2x} \). **Options:** (a) \( 1 + 2x - \frac{2^2}{2!}x^2 + \frac{2^3}{3!}x^3 + \cdots \) (b) \( 2x + \frac{2^2}{3!}x^2 - \frac{2^3}{4!}x^3 + \cdots \) (c) \( 1 - 2x + \frac{2^2}{2!}x^2 - \frac{2^3}{3!}x^3 + \cdots \) (d) \( 1 - 2x + \frac{2^2}{2!}x^2 - \frac{2^3}{3!}x^3 + \cdots \) **Explanation:** The task is to determine which of the given options correctly represents the Maclaurin series expansion for the function \( e^{-2x} \).
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