I.Answer and show the solution of the following problems.Capacitance: (farad) orSeries CircuitsParallel Circuits(C/V)VT=Vi+Vzt...VT=VI=V2+Ceq=Ci+C2t.%3DWork, Znergy (U)Cea C,C2U =Q V2 C21. A 30 µ7 capacitor is connected to a 9.0 V battery.Calculate the charge on the capacitor.How many excess electrons are there on the negative plate of the capacitor?(Zlementary charge e = 1.6 x 10-19 C)The p.d. across a capacitor is 3.0 V and the charge on the capacitor is 150 nC.Determine the charge on the capacitor when the p.d. is:a.b.2.a.6.0 VЬ.3. A 1000 µF capacitor is charged to a potential difference of 9.0 V.Calculate the energy stored by the capacitor.b.9.0 Va.Determine the energy stored by the capacitor when the p.d. across it is doubled.For each circuit below, determine the total capacitance of the circuit.4.b100µF500UF10pF50 uF 100µFHHEHHHEa20 nF50 ul500 uF 100µFd50 µF40 uF50 uF50µF1.5 V500uF100µF5.The diagram shows an electrical circuit.

(a) The charge(Q) on the capacitor. (b) No. of excess electrons on the negative plate of the…

1. A 30 µF capacitor is connected to a 9.0 V battery. Calculate the charge on the capacitor. a. How many excess electrons are there on the negative plate of the capacitor? (Elementary charge e = 1.6 x 10-19 C) b.

1. A 30 µF capacitor is connected to a 9.0 V battery. Calculate the charge on the capacitor. a. How many excess electrons are there on the negative plate of the capacitor? (Elementary charge e = 1.6 x 10-19 C) b.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Electrostatic Potential and Capacitance

An electrostatic force is a force caused by stationary electric charges /fields. The electrostatic force is caused by the transfer of electrons in conducting materials. Coulomb’s law determines the amount of force between two stationary, charged particles. The electric force is the force which acts between two stationary charges. It is also called Coulomb force.

Question

I.
Answer and show the solution of the following problems.
Capacitance: (farad) or
Series Circuits
Parallel Circuits
(C/V)
VT=Vi+Vzt...
VT=VI=V2
+
Ceq=Ci+C2t.
%3D
Work, Znergy (U)
Cea C,
C2
U =
Q V
2 C
2
1. A 30 µ7 capacitor is connected to a 9.0 V battery.
Calculate the charge on the capacitor.
How many excess electrons are there on the negative plate of the capacitor?
(Zlementary charge e = 1.6 x 10-19 C)
The p.d. across a capacitor is 3.0 V and the charge on the capacitor is 150 nC.
Determine the charge on the capacitor when the p.d. is:
a.
b.
2.
a.
6.0 V
Ь.
3. A 1000 µF capacitor is charged to a potential difference of 9.0 V.
Calculate the energy stored by the capacitor.
b.
9.0 V
a.
Determine the energy stored by the capacitor when the p.d. across it is doubled.
For each circuit below, determine the total capacitance of the circuit.
4.
b
100µF
500UF
10pF
50 uF 100µF
HHE
HHHE
a
20 nF
50 ul
500 uF 100µF
d
50 µF
40 uF
50 uF
50µF
1.5 V
500uF
100µF
5.
The diagram shows an electrical circuit.

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