1. 56 g of iron (III) sulfate reacts with 24 g of lead (IV) nitrate to form iron (III) nitrate and lead (IV) sulfate Find. a. TY of iron (III) nitrate b. TY of lead (IV) sulfate c. Which is the limiting reactant? d1. Percent yield of iron (III) nitrate if the AY is 16.5 g. d2. percent Yield of lead (IV) sulfate if the AY is 20
1. 56 g of iron (III) sulfate reacts with 24 g of lead (IV) nitrate to form iron (III) nitrate and lead (IV) sulfate Find. a. TY of iron (III) nitrate b. TY of lead (IV) sulfate c. Which is the limiting reactant? d1. Percent yield of iron (III) nitrate if the AY is 16.5 g. d2. percent Yield of lead (IV) sulfate if the AY is 20
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Transcribed Image Text:1. 56 g of iron (III) sulfate reacts with 24 g of lead
(IV) nitrate to form iron (III) nitrate and lead (IV)
sulfate
Find.
a. TY of iron (II) nitrate
b. TY of lead (IV) sulfate
c. Which is the limiting reactant?
d1. Percent yield of iron (III) nitrate if the AY is 16.5
g.
d2. percent Yield of lead (IV) sulfate if the AY is 20
Transcribed Image Text:PERCENT YIELD
How many grams or moles of products are produced in a chemical reaction? This can te
answered through stoichiometric conversions
Directions: Solve the given word problems below. Write your complete solutions and box your
final answer.
1. 56 g of iron (III) sulfate reacts with 24 g of lead (IV) nitrate.
a. Calculate the mass of iron (III) nitrate in g.
b. Calculate the mass of lead (IV) sulfate in g.
c. Which of these are the limiting reagent and excess reactant?
d. Calculate the percent yield of the reaction
Fez(SO4), + Pb(NO3)4 → Fe(NO3)3 + Pbz(SO4)4
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